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Andre45 [30]
3 years ago
9

Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w

hy it is not possible for a right triangle to have legs with lengths of 16 and an odd number.
Mathematics
1 answer:
Arte-miy333 [17]3 years ago
4 0
Let k be an integer. Suppose there is a triangle with legs of length 16 and 2k+1. Then by the Pythagorean theorem, the length of the hypotenuse should be

\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if x=16 and y=2k+1 are integers, then so are x^2-y^2, 2xy, and x^2+y^2.

However, 4k^2+4k+257 is not a perfect square trinomial, which means for any integer k, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.
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Factorization is a method of writing numbers as the product of their factors or divisors.

<em><u>Solution:</u></em>

<em><u>Factorisation:</u></em>

Factorization is a method of writing numbers as the product of their factors or divisors.

In other words we can say, Finding what to multiply together to get an expression.

It is like "splitting" an expression into a multiplication of simpler expressions.

<em><u>Methods of factorisation:</u></em>

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  • The sum-product pattern
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<em><u>Factoring out the GCF:</u></em>

This methods means that factoring out common factors

For example:

12x^2 + 3x = 3x(4x + 1)

This can be used when each term in given expression shares a common factor

<em><u>The sum-product pattern</u></em>

A quadratic equation may be expressed as a product of two binomials

For example:

x^2 + 7x + 12 = (x + 3)(x + 4)

This method can be used for quadratic equations of form ax^2 + bx + c = 0

<em><u>The grouping method</u></em>

If the polynomial is of the form  ax^2 + bx + c and there are factors of ac that add up to b , we can use this method

For example:

2x^2 + 7x + 3\\\\2x^2 + 6x + 1x + 3\\\\2x(x + 3) + 1(x + 3)\\\\(x + 3)(2x + 1)

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If the first and last terms are perfect squares and the middle term is twice the product of their square roots , we can use this method

For example:

x^2 + 10x + 25\\\\(x + 5)^2

<em><u>The difference of squares pattern</u></em>

If the expression represents a difference of squares, we can use this method

Because a^2 - b^2 = (a + b)(a - b)

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x^2 - 25\\\\x^2 - 5^2\\\\(x + 5)(x - 5)

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Step-by-step explanation:

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Answer:

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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