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Dafna11 [192]
2 years ago
6

Find the area bounded by the graphs of the indicated equations over the given interval.

Mathematics
1 answer:
NeX [460]2 years ago
8 0

Answer:

48

Step-by-step explanation:

y = 0

is basically the horizontal axis.

First, find the integral of x^2-25.

Remember that

integral of a constant is that constant times x.

Also that

to take the integral of a power function, add 1 to the degree and divide by that same degree.

y =  {x}^{2}  - 25

We then get

\frac{ {x}^{3} }{3}  - 25x

Evaluate at -3

\frac{ - 3 {}^{3} }{3}  - 25( - 3)

- 27 + 75 = 48

Then we evaluate at 0

\frac{0 {}^{3} }{3}  - 25(0) = 0

Next, we subtract the the answer then we get

48 - 0 = 48

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If x= -4, find the value of x²-5+6.​
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Answer:

x^2_5+6

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Step-by-step explanation:

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Answer:

a) Null hypothesis:\mu_{1} \leq \mu_{2}

Alternative hypothesis:\mu_{1} > \mu_{2}

b) z_{crit}=2.33

And since the calculated value is lower than the critical value we have enough evidence at 0.01 of significance to FAIL to reject the null hypothesis.

Step-by-step explanation:

Part a

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

We want to test this:

Null hypothesis:\mu_{1} \leq \mu_{2}

Alternative hypothesis:\mu_{1} > \mu_{2}

Part b

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Data given and notation

\bar X_{1}=15 represent the mean for the sample 1

\bar X_{2}=14 represent the mean for the sample 2

\sigma_{1}=2 represent the population deviation for 1

\sigma_{2}=3 represent the population deviation for 2

n_{1}=64 sample size selected for 1

n_{2}=64 sample size selected for 2

\alpha=0.01 represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

The statistic is given by:

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}     (1)

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z_{crit}=2.33

And since the calculated value is lower than the critical value we have enough evidence at 0.01 of significance to FAIL to reject the null hypothesis.

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