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2 years ago

Which set of ordered pairs don’t represent a function

Mathematics

1 answer:

babunello [35]2 years ago

4 0

Answer:

The first multiple-choice doesn't represent a function

Step-by-step explanation:

(-4,3),(1,-6),(-8,-1),(1,9)

because a function has two pairs with the same x value

*hope that makes sense*

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Convert 4 oz into pounds

Molodets [167]

4 Oz / 16 = 0.25 lbs

4 ounces in pounds is 0.25

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2 years ago

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True or False:

Lostsunrise [7]

The answer is true to all of them.

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3 years ago

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I need help proving this ASAP

Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

$\tan(x + \frac{3\pi}{2} ) = - \cot \: x$

One way is to use the basic double angle formula:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) \cos( \frac{3\pi}{2} ) + \cos(x) \sin( \frac{3\pi}{2}) }{\cos(x) \cos( \frac{3\pi}{2} ) - \sin(x) \sin( \frac{3\pi}{2}) }$

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) ( 0) + \cos(x) ( - 1) }{\cos(x) (0) - \sin(x) ( - 1) }$

We simplify further to get:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ 0 - \cos(x) }{0 + \sin(x) }$

We simplify again to get;

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{- \cos(x) }{ \sin(x) }$

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$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = - \cot(x)$

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3 years ago

HELP PLS! whoever gets it right gets brainliest!!

galben [10]

Answer: Pretty sure it is 3

Step-by-step explanation:

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irina [24]

Answer:

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Step-by-step explanation:

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→ Since there are no factors utilise the quadratic formula

$\frac{-b+-\sqrt{b^{2}-4ac } }{2a}$

→ List the values of a, b and c

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3 years ago

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