No because the 3 is the tens place. So its supposed to 3 ten blocks
X^2-11x+28=0
(x-7)(x-4)=0
x-7=0
x=7
x-4=0
x=4
Answer:
4.
Step-by-step explanation:
I will have one real root = fifth root of 3.
As it has a total of 5 roots ( By the Fundamental Theorem of Algebra) then it must have 4 complex roots.
Answer:
Step-by-step explanation:
Y=2x is linear (also proportional) since it involves only the first power of x
2x^2 is not linear, due to the second power of x (x^2); it is quadratic
Y = 1/x is not linear, due to x being in the denominator.