<h2>
Equation for a circle with center (0, −4) and radius 8 is x²+y²+8y-48 = 0</h2>
Step-by-step explanation:
Equation of circle with (h,k) as center and radius r is given by,
(x-h)²+(y-k)² = r²
Here we need to find equation for a circle with center (0, −4) and radius 8.
Center = (h,k) = (0, −4)
Radius = r = 8
Substituting in equation
(x-h)²+(y-k)² = r²
(x-0)²+(y-(-4))² = 8²
x²+(y+4)² = 64
x²+y²+8y+16 = 64
x²+y²+8y-48 = 0
Equation for a circle with center (0, −4) and radius 8 is x²+y²+8y-48 = 0
Answer:
61.973
Step-by-step explanation:
let the unknow side be x
surf of prism = 2*(8*8+8x+8x) = 2*(64+16x) = 128+ 32x
again, surface of cylinder = 2pi*r*(r+h) = 2 * pi * 14 * (14+10) = 672pi
now solve for x, when
128+32x = 672pi
Answer:
Option 3.
Step-by-step explanation:
The given function is
where, h(t) is the height of a small rock falling from the top of a 124-ft-tall building and t is the time in seconds.
It is a downward parabola.
Equate the function equal to 0, to find the time at which the rock touch the ground.
If 
, the according to the quadratic formula
Using quadratic formula, we get
Time cannot be negative. So, the rock remain in the air in the interval 0 < t < 2.
Therefore, the correct option is 3.
