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tino4ka555 [31]
2 years ago
13

Is it just me or does anyone else feel like they made someone offended or confused or something like that when someone replies b

ack, "ok"
Like when ur trying to be funny and someone replies back, "ok"
What vibe do you get?
Brainliest to best answer!
Plus 100 points!
Mathematics
2 answers:
DochEvi [55]2 years ago
4 0

Answer:

I say "ok" to my parents when they ask a question as a joke, but that has happened to me and it's just annoying. If you don't find it funny then don't laugh at all and don't say anything-

Marta_Voda [28]2 years ago
3 0

Answer:

OMG IT'S NOT JUST YOU GURL- SAME HERE LOL

-

When someone replies "ok" and I'm trying to like make them laugh lol- it just gives me the "dead" and "dreadful" vibe.  Like- it didn't make them laugh or something....or maybe my joke wasn't funny.  Or even- it just like makes me think- "wait- did they just like not understand my joke?"  Which gives me the "wait-" vibe.

-

SORRY IF YOU DIDN'T UNDERSTAND WHAT I SAID-

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PLEASE HELP !!
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Answer:

<u>200</u>

Step-by-step explanation:

pi · radius · height

3.14 · 8 · 25 = 200

extra : i used symbolab.com :)

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3 years ago
What are the partial profucts of 42x28
Alona [7]
I multipled 42*28 and i got 1176
3 0
4 years ago
Simplify (2^3)^-2<br> A -1/64<br> B 1/64<br> C 2<br> D 64
romanna [79]
The answer is B hope this helps you.
3 0
3 years ago
Read 2 more answers
Q1 : Find the inverse of the function.
Mamont248 [21]

Answer:

1. Option D is correct.

2. Option B is correct.

3. Option B is correct.

Step-by-step explanation:

Inverse function defined as the the function that undergoes the action of the other function.

A function f^{-1} is the inverse of f if whenever y =f(x) and x =f^{-1}

To find the inverse of the function:

Q1.

Given the function:  f(x) = 7x -1

Put y for f(x) and solve for x;

y= 7x -1

Add 1 both sides we get;

y + 1 = 7x

Divide both sides by 7 we get;

x = \frac{y+1}{7}

Put f^{-1}(y) for x;

f^{-1}(y) = \frac{y+1}{7}

Interchange y =x, we have

f^{-1}(x) = \frac{x+1}{7}

Q 2.

Given the function:

f(x) = x^3 - 7

Put y for f(x) and solve for x;

y = x^3-7

Add 7 both sides we get;

y + 7 =x^3

taking cube root both sides we get

x =\sqrt[3]{y+7}

Put f^{-1}(y) for x;

f^{-1}(y) =\sqrt[3]{y+7}

Interchange y =x, we have

f^{-1}(x) = \sqrt[3]{x+7}

Q3 .

Given the function:

f(x) = 5x^3 - 3

Put y for f(x) and solve for x;

y = 5x^3-3

Add 3 both sides we get;

y + 3 =5x^3

Divide both sides by 5 we get;

x^3 = \frac{y+3}{5}

taking cube root both sides we get

x = \sqrt[3]{\frac{y+3}{5} }

Put f^{-1}(y) for x;

f^{-1}(y) = \sqrt[3]{\frac{y+3}{5} }

Interchange y =x, we have

f^{-1}(x) = \sqrt[3]{\frac{x+3}{5} }




7 0
3 years ago
Solve this for me <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B1989%20%5Cdiv%201989%20%5Ctimes%201%20%2B%201%20%5Ctimes%20
gtnhenbr [62]
<h2><u>Answer</u>:</h2>

\large\tt\sqrt{2}

\begin{gathered} \: \end{gathered}

<h2><u>Explanation:</u></h2>

\large\tt\sqrt{ 1989 \div  1989 \times  1+1 \times  1  }

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\large\tt\sqrt{1\times 1+1\times 1}

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\large\tt\sqrt{1+1}

  • And add 1 and 1 to get 2.

\large\tt\sqrt{2}

\begin{gathered} \: \end{gathered}

8 0
3 years ago
Read 2 more answers
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