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Natalka [10]
2 years ago
12

1+ cos^4 x-sin^4 x = 2 cos² x​

Mathematics
1 answer:
Mariana [72]2 years ago
7 0

\text{L.H.S}\\\\=1+ \cos^4 x - \sin^4 x\\\\=1+ (\cos^2 x)^2 - (\sin^2 x)^2\\\\=1+(\cos^2 x + \sin^2 x)(\cos^2 x- \sin^2 x)\\\\=1+1\cdot(\cos 2x)\\\\=1+\cos 2x\\\\=2\cos^2 x\\\\=\text{R.H.S}\\\\\text{Proved.}

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Someone plz help<br>what is N<br>-8n+4(1+5n)=-6n-14
klemol [59]

Answer:

n=-1

Step-by-step explanation:

-8n+4(1+5n)=-6n-14

-8n+4+20n=-6n-14

12n+4=-6n-14

12n+6n=-14-4

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4 0
3 years ago
Please help. How do I solve this?
LuckyWell [14K]
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3 years ago
Which of the following shows the correct steps to find the value of 16^1/4
Scorpion4ik [409]
The answer is B, I hope this helps! (don't forget to give brainliest)

4 0
4 years ago
13) If AOBC is a rectangle whose three vertices are A(0,3), (0,0) and B(5,0).
Levart [38]

Answer:

(b) 68

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Diagonal:

Diagonals are a line between opposite points in a square.

In this question, it is between A(0,3) and B(5,0), and between (0,0) and (5,3). Both these diagonals have the same measure, and are the distance between these points. So

D = \sqrt{(5-0)^2+(3-0)^2} = \sqrt{5^2 + 3^2} = \sqrt{34}

Then sum of the squares of its both diagonals is units

Both diagonals measure \sqrt{34}. Sum of squares is:

(\sqrt{34})^2 + (\sqrt{34})^2 = 34 + 34 = 68

The correct answer is given by option b.

6 0
3 years ago
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Burka [1]

Answer:

X=number of hours

Step-by-step explanation:

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$65 per hour

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3 0
4 years ago
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