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2 years ago

Write an equation that shows the relationship between cost in dollars (y) and weight (x).

Mathematics

1 answer:

lakkis [162]2 years ago

7 0

I’m not sure about this one

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Do you guys know the answer ?

MrMuchimi

X=-2y+1
x=y-5
so, both are equal

-2y+1=y-5
-3y=-6

so y=2
and x= -3

7 0

2 years ago

The value of the 4th term is 80. The sequence is doubling at each step. (Please answer this is due tomorrow)

Lyrx [107]

The value of the 5th term of the geometric sequence is of 160.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

$a_n = a_1q^{n-1}$

In which $a_1$ is the first term.

We already have the 4th term and the common ratio, hence the 5th term is given by:

80 x 2 = 160.

The value of the 5th term of the geometric sequence is of 160.

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

6 0

1 year ago

Enid got a job through an employment agency that charges a fee equal to 40% of the ﬁrst ﬁve weeks’ pay. The job pays $315 per we

pantera1 [17]

Enid has to pay the employment agency $625

8 0

2 years ago

Read 2 more answers

What is the GCF of and 55 and 80 *

Zarrin [17]

The Greatest Common Factor of 55 and 80 is 5.

3 0

2 years ago

A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s

Umnica [9.8K]

Answer:

88.51 is the minimum score needed to receive a grade of A.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73

Standard Deviation, σ = 11

We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.0793.

$P( X \geq x) = P( z \geq \displaystyle\frac{x - 73}{11})=0.0793$

$= 1 -P( z \leq \displaystyle\frac{x - 73}{11})=0.0793$

$=P( z \leq \displaystyle\frac{x - 73}{11})=0.9207$

Calculation the value from standard normal z table, we have,

$P(z \leq 1.410) = 0.9207$

$\displaystyle\frac{x - 73}{11} = 1.410\\x =88.51$

Hence, 88.51 is the minimum score needed to receive a grade of A.

3 0

2 years ago