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2 years ago

What expression is equivalent to (3n-4)-2(n-2)

Mathematics

1 answer:

jeka57 [31]2 years ago

6 0

(1n-4)-2(n-0) because you will subtract 2 from the numbers in the parentheses

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Im on a test and i need the answer really bad please help me out

mash [69]

I’m not sure but good luck with your test

6 0

2 years ago

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20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

2 years ago

When designing a play area the mother created a scale drawing in which the side that measures 6 feet was represented by 3 inches

Svetach [21]

Answer:

12 inches

Step-by-step explanation:

if it is a square then you do 3×4 to get the perimeter

6 0

3 years ago

Pls help extra points and mark brainlist

juin [17]

Answer:

it is c none of the above

Step-by-step explanation:

4 0

2 years ago

Which expression is equivalent to sqrt128x^5y^6/2x^7y^5 ? Assume x 0 and y > 0.

kolbaska11 [484]

<u>Answer:</u>

$\frac{8\sqrt{y} }{x}$

<u>Step-by-step explanation:</u>

We are given the following expression and we are to simplify it:

$\sqrt {\frac {128x^5y^6} {2x^7y^5} }$

To make it easier to solve, we can also write this expression as:

$\sqrt {\frac{128}{2} * \frac {x^5} {x^7} * \frac {y^6} {y^5}}$

Now we will cancel out the like terms to get:

$\sqrt {64*\frac{1} {x^2}*y }$

Taking the square root of the terms to get:

$8*\frac {1}{x} .\sqrt{y}$

$\frac{8\sqrt{y} }{x}$

4 0

3 years ago

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