The answer is "C", "MW".
In the given problem, the place QMW and plane RMW. These planes intersect at MW, in which intersection is either a point, line or curve that an entity or entities both possess or is in contact with but if we see in Euclidean<span> geometry, the intersection of two planes is called a “line”. </span>In the plane we can understand that the common line for both plane QMW and plane RMW is MW.
2x + 3y = 6 <=>
3y = -2x + 6 <=>
y = -2/3x + 6/3 <=>
y = -2/3x + 2
The answer is the first one.
The equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5².
Based on the calculations, the equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5²
The equation of a circle.
Mathematically, the standard form of the equation of a circle is given by;
(x - h)² + (y - k)² = r²
Where:
h and k represent the coordinates at the center.
r is the radius of a circle.
The midpoint of the given points represents the center of this circle:
h = (4 + 4)/2 = 4
k = (5.5 + 10.5)/2 = 8
Next, we would determine the radius by using the distance formula for coordinates:
r = √[(x₂ - x₁)² + (y₂ - y₁)²]
r = √[(4 - 4)² + (10.5 - 5.5)²]
r = √[0² + 5²]
r = √25
r = 5 units.
Therefore, the equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5².
Learn more about circle here: brainly.com/question/12823137
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First we need to isolate the variable so we add 15 to both sides which is
w/4=43 then we need to multiply by 4 to both sides so its 4w=172
then divide by 4 which is 43 so the answer is w=43
Answer:
7^12
Step-by-step explanation:
7^14
-----------
7^2
When we divide with the same base, we subtract the exponents
7^(14-2)
7^12
