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denis-greek [22]
3 years ago
6

Alex is decorating a circular cake. She wants to place a triangle with the longest possible side within the circle. The radius o

f the circle is 4.5 inches. What is the longest side of the triangle measure?
Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0
2 inches i think. jkjjjhgknhkngujnvv
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Find the area of a square with a side length of 8 inches. a. A = sq. in. c. A = 64 cu. sq. in. b. A = 64 sq. in. d. none of the
kirill [66]

Area of a square = (side)² or = (side*side)

Area of the square = (8 inch)² = 8*8 inch² = 64 inch²

Answer is 64 sq. in.

7 0
3 years ago
Read 2 more answers
For the vectors u and v with magnitudes u = 88 and v = 99​, find the angle θ between u and v which makes u and v = 77.
WARRIOR [948]

Answer:

<h2>89.5°</h2>

Step-by-step explanation:

Using the vector formula u.v = |u||v|cos\theta

|u| = magnitude of vector u

|v| = magnitude of vector v

u.v is the dot product of vector u and v

Given |u| = 88, |v| = 99 and u.v = 77, to get \theta we will substitute the given values into the equation above;

77 = 88*99cos\theta\\cos\theta = \frac{77}{88*99} \\cos\theta = \frac{77}{8712} \\cos\theta = 0.008838\\\theta = cos^{-1} 0.008838\\\theta = 89.5^{0}

4 0
2 years ago
(2/5) to the 2 power
marta [7]

Answer:

0.16

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The school auditorium can hold at most 480 people. There were 185 advance tickets sold for the school play. Write and solve an i
attashe74 [19]

Answer:

p + 185 ≤ 480

p ≤ 295

At most 295 people can attend the play

Step-by-step explanation:

3 0
2 years ago
Please help! Thanks in advance.
alukav5142 [94]
In this problem, we need to plug in the given x values for f(x)=0 and find a and b.

When we plug in 1, we get: 2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0

Simplify:
2 - 5 - 14 + a + b = 0
- 17 + a + b = 0
a + b = 17

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0
512 - 320 - 224 + 4a + b = 0
- 32 + 4a + b = 0
4a + b = 32

Now we have our second one. We can combine them:
a + b = 17 \\ 4a + b = 32

I use elimination method which is easier here.

Multiply the top equation by -1: - a - b = - 17 \\ 4a + b = 32

Add them up:
3a = 15

Simplify:
a = 5

Now we have a, we can plug in one of those equations to find b:
5 + b = 17
b = 17 - 5
b = 12

So, the answers are a=5 and b=12 .
6 0
3 years ago
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