2 years ago

A=(1+1/2).(1+1/3). ... .(1+1/2020)

1 answer:

5 0

$A=\left(1+\dfrac{1}{2}\right)\cdot \left(1+\dfrac{1}{3}\right)\cdot\ldots\cdot \left(1+\dfrac{1}{2020}\right)=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\ldots\cdot \dfrac{2021}{2020}=\dfrac{\dfrac{2021!}{2}}{2020!}=\\\\=\dfrac{2021}{2}=1010.5$

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