Answer:
156 players
Step-by-step explanation:
The 9 players for baseball and 11 players for football are added. 9 + 11 = 20.
Once you have 20, you can multiply it by the 6 schools. Which gets you 120 players so far.
After you multiply the 4 schools by the 9 players for baseball. You’ll get 36. Add the 120 players to 36 players and you’ll get 156 players for the 10 schools in total
Answer:
Randomly selecting a six of diamonds - 1 / 52
Randomly selecting a 7, 8, 9 or 10 - 4 / 13
Step-by-step explanation:
There is only 1 six of diamonds in a standard deck of cards. There are 52 cards in a deck, thus the probability of pulling a six of diamonds is 1 in 52.
There are 4 of each card in a deck. so they are 4 7's, 4 8's. 4 9's and 4 10's. And there are a total of 52 cards in a deck. So the probability of pulling a 7,8,9 or 10 are 4 + 4 + 4 + 4 in 52
4 + 4 + 4 + 4 = 16
16 / 52 simplified is 4 / 13 Therefore the is a 4 in 13 chance of pulling a 7 8 9 or 10
The other ones are correct
Answer:
The expected number of appearance defects in a new car = 0.64
standard deviation = 0.93(approximately)
Step-by-step explanation:
Given -
7% had exactly three, 11% exactly two, and 21% only one defect in cars.
Let X be no of defects in a car
P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21
P(X=0 ) = 1 - .07 - .11 - .21 = 0.61
The expected number of appearance defects in a new car =
E(X) =
=
= 0.64
= variation of E(X) =
= 
=
= 0.8704
standard deviation =
=
= 0.93(approximately)
Answer:
The answer most likely would be x > -3
Step-by-step explanation:
It would be this because it's a opened dot and not a closed one. A closed dot would have the greater or less than sign with the line underneath it
REMEMBER if it is shaded to the right then the inequality points to the right (>). If it is shaded to the left the inequality points to the left (<)
HOPE THIS HELPS
<h3>Answer:</h3>
The rate of change in the 2nd 3-year interval is 3.375 times that in the 1st 3-year interval.
<h3>Explanation:</h3>
The exponential function tells you that each year values get multiplied by 1.5. Then after thee years, values are multiplied by 1.5³ = 3.375. This is true for all function values, including average rate of change. Whatever the rate of change is in years 0–3, it will be 3.375 times that in years 3–6.
The calculation performed by the graphing calculator confirms this:
... the average rate of change in years 3–6 is 160.3125; in years 0–3, it is 47.5.
The ratio of these average rate of cange values is 3.375.