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Eddi Din [679]
2 years ago
9

A 4-digit combination lock can be opened only if a correct combination of digits from 0-9 is chosen. Find the probability of gue

ssing the correct combination if: none of the digits are repeated, any of the digits can be repeated, any of the digits can be repeated but the 3 and 8 are not in the combination.
Mathematics
1 answer:
erastova [34]2 years ago
4 0

The probabilities are as follows:-

  • if none of the digits is repeated 0.504
  • If any of the digits can be repeated 1
  • If any of the digits can be repeated but the 3 and 8 are not in the combination 0.24.
<h3></h3><h3>What is probability?</h3>

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

The probability will be calculated as follows:-

Total combinations are = 10⁴ = 10000

A) if none of the digits are repeated:-The combinations will be 10 x 9 x 8 x 7 = 5040

Probability =  5040 /  10000

Probaility = 0.504

B) If any of the digits can be repeated:- The combinations will be 10 x 10 x 10 x 10 = 10000

Probabilityy = 10000 / 10000 = 1

C )If any of the digits can be repeated but the 3 and 8 are not in the combination the combinations will be 7 x 7 x 7 x 7 = 2401

Probability = 2401 / 10000 = 0.24

Therefore if none of the digits is repeated 0.50.If any of the digits can be repeated 1.If any of the digits can be repeated but the 3 and 8 are not in the combination 0.24.

To know more about probability follow

brainly.com/question/24756209

#SPJ1

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Pani-rosa [81]

Answer:

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Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by P(Z>\frac{(25-27)}{3.29})

What is the probability of success of a single trial of this experiment?

Options:

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Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

\mu =\frac{np}{\sigma}=\sqrt{np(1-p)}

now,

Z=\frac{X-\mu}{\sigma}

so,

by comparing with P(Z>\frac{(25-27)}{3.29}), we get:

μ=np=27

\sigma=\sqrt{np(1-p)} =3.29

put np=27

we get:

\sigma=\sqrt{27(1-p)} =3.29

take square on both sides:

10.8241=27-27p

27p=27-10.8241

p=0.6

Which is the probability of success of a single trial of the experiment

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3 years ago
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