Answer:
6 feet.
Step-by-step explanation:
Dimensions of the Pool =80 feet long by 20 feet wide
Area of the walkway =1344 square feet.
If the width of the walkway=w
- Length of the Larger Rectangle =80+2w
- Width of the Larger Rectangle =20+2w
Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

Answer:
a
Step-by-step explanation:
We can see that window is in shape of rectangle. So the length of the required wood to frame window is equal to the perimeter of rectangle.
SO the length of rectangular window is

feet.
Width of the rectangular window is =

feet.
In general parameter of rectangle is =

So the parameter of window is =

So the required length of wood to frame window is = 28.834 feet