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lana [24]
3 years ago
6

I really need help with this one it says 8 of the beads are purple in case it's hard to see

Mathematics
2 answers:
Harman [31]3 years ago
7 0
48% of the beads are purple
liraira [26]3 years ago
7 0
First of all, ask google before anything but im guessing the answer is 11 because I have 400k on insta and 90k on youtube subscribe! merch link in description
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Suppose a population consists of 50,000 people. Which of the following
Bogdan [553]

Answer:

The number that would represent a sample statistic of a population but not a parameter is:

O A. Neither 500 nor 50,000

Step-by-step explanation:

The reason behind this is that a parameter has to follow a certain guideline because it needs to fulfill a rule to be considered one. There has to be a correlation, so if we have no clear establishment the number can't be a parameter. Thus, 500 would be the minimum 1% to be considered as a parameter and 50,000 the whole universe of the population. They keep a correlation, therefore any number but they would be a sample statistic.

3 0
3 years ago
Which fractions are equivalent to <br> 6/8?
Scilla [17]

Answer:

3/4

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Simplify the Expression I WILL GIVE BRAINLYIST!!!!!
sweet-ann [11.9K]
1+5×3/2
=1+15/2
=16/2
=8
Your answer is option A. 8.
7 0
2 years ago
Read 2 more answers
Which system of linear inequalities Is represented by this graphed solution?
SashulF [63]

Answer:

y ≥ 3x - 1

y < -\frac{1}{2}x+2

Step-by-step explanation:

Let the equation of the solid line passing through (x', y') given in graph is,

y = mx + b

Here m = slope of the line

b = y-intercept

Slope of the solid line =

                                 m = \frac{3}{1}

                                 m = 3

y - intercept 'b' = -1

Therefore, equation of the line will be,

y = 3x - 1

Since, shaded (blue) area is above the line, inequality that will represent the solution area will be,

y ≥ 3x - 1

For the dotted line,

Slope of the line (m) = \frac{\text{Rise}}{\text{Run}}

                                  = \frac{-2}{4}

                                  = -\frac{1}{2}

y-intercept (b) = 2

Equation of the dotted line → y = -\frac{1}{2}x+2

Since, shaded (grey color) area is below the dotted line,

Inequality representing the solution area will be,

y < -\frac{1}{2}x+2

7 0
3 years ago
Three cell phones towers can be modeled by the points X(6,0), Y(8,4), and Z(3,9). Determine the location of another cell phone t
Marat540 [252]

Answer:

The location of the new cell phone tower is (h,k) = (3,4), and the equation of the circle is x^{2}+y^{2} -6\cdot x - 8\cdot y = 0.

Step-by-step explanation:

The location of the cell phone tower coincides with the location of a circunference passing through the three cell phone towers. By Analytical Geometry, the equation of the circle is represented by the following general formula:

x^{2} + y^{2}+A\cdot x + B\cdot y +C = 0 (1)

Where:

x - Independent variable.

y - Dependent variable.

A, B, C - Circunference constants.

Given the number of variable, we need the location of three distinct points:

(x_{1},y_{1}) = (6,0)

36 +6\cdot A + C = 0

(x_{2},y_{2}) = (8,4)

80 + 8\cdot A + 4\cdot B + C = 0

(x_{3},y_{3}) = (3,9)

90 + 3\cdot A + 9\cdot B + C = 0

Then, we have the following system of linear equations:

6\cdot A + C = -36 (2)

8\cdot A +4\cdot B + C = -80 (3)

3\cdot A + 9\cdot B + C = -90 (4)

The solution of this system is:

A = -6, B = -8, C = 0

By comparing the general form with the standard form of the equation of the circunference is:

A = -2\cdot h (5)

B = -2\cdot k (6)

C = h^{2}+k^{2}-r^{2} (7)

Where:

h, k - Coordinates of the center of the circle.

r - Radius of the circle.

If we know that A = -6, B = -8 and C = 0, then coordinates of the center of the circle and its radius are, respectively:

h = -\frac{A}{2}

k = -\frac{B}{2}

r = \sqrt{h^{2}+k^{2}-C}

h = 3, k = 4, r = 5

The location of the new cell phone tower is (h,k) = (3,4), and the equation of the circle is x^{2}+y^{2} -6\cdot x - 8\cdot y = 0.

3 0
2 years ago
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