The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Equal to 4.73 repeating, rounded is 4.7
The equilibrium constant of the reaction is 0.0030.
The equation of the reaction is given as;
N2(g) + 3H2(g) ⇆ 2NH3 (g)
We have the following information at equilibrium;
[NH3] = 0.105 M
[N2] = 1.1 M
[H2] = 1.50 M
Hence, we can calculate the equilibrium constant using the relation;
K = [NH3]^2/ [N2] [H2]^3
Substituting values;
K = [0.105]^2/[ 1.1] [1.50]^3
K =0.011025 /3.7125
K= 0.0030
Learn more: brainly.com/question/17960050
Answer: Here is the complete table, with the filled in values:
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Time (h) Distance (mi)
3 2
9 6
12 8
18 12
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Explanation:
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Let us begin by obtaining the "?" value; that is, the "distance" (in "mi.") ;
when the time (in "h") is "18" ;
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12/8 = 18/?
Note: "12/8 = (12÷4) / (8÷4) = 3/2 ;
Rewrite: 3/2 = 18/? ; cross-multiply: 3*? = 2 * 18 ;
3*? = 36 ;
Divide each side by "3" ;
The "?" = 36/3 = 12 ;
So, 12/8 = 18/12 ;
The value: "12" takes the place for the "?" in the table for "distance (in "mi.);
when the "time" (in "h") is "18".
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Now, let us obtain the "? " value for the "distance" (in "mi.");
when the "time" (in "h") is: "9" .
12/8 = 9/? ; Solve for "?" ;
We know (see aforementioned) that "12/8 = 3/2" ;
So, we can rewrite: 3/2 = 9/? ; Solve for "?" ;
Cross-multiply: 3* ? = 2* 9 ; 3* ? = 18 ;
Divide each side by "3" ;
to get: "6" for the "?" value.
When the time (in "h") is "9", the distance (in "mi.") is "6" .
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Now, to solve the final "?" value in the table given.
9/6 = ?/2 ; Note: We get the "6" from our "calculated value" (see above problem).
9/6 = (9÷3) / (6÷3) = 3/2 ;
So, we know that the "?" value is: "3" .
Alternately: 9/6 = ?/2 ;
Cross-multiply: 6*? = 2*9 ; 6 * ? = 18 ; Divide each side by "6" ;
to find the value for the "?" ;
"?" = 18/6 = "3" .
When the "distance" (in "mi.") is: "2" ; the time (in "h") is: "3" .
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Here is the complete table—with all the values filled in:
____________________________________________________
<span>Time (h) Distance (mi)
____________________________________________________
3 2
9 6
12 8
18 12
____________________________________________________</span>
Your answer would be 63.585 sq meters
Hope this helps!
