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2 years ago

Complete the steps to evaluate log798, given log72 ≈ 0.356. how can you rewrite log798 using the product property?

Mathematics

2 answers:

Valentin [98]2 years ago

4 0

The expression $\rm log_{7} 98$ using the product property is $\rm log_{7} 49 + \rm log_{7} 2$ .

<h3>What is a logarithm?</h3>

A logarithm is the exponentiation inverse function that can be expressed by the exponent or power to which a base must be raised to yield a number.

It is given that $\rm log_{7} 2$ = 0.356

We can write $\rm log_{7} 98$ in terms of $\rm log_{7} 2$

$\rm log_{7} 98$ = $\rm log_{7} (49\times 2)$

In logarithm, the product will change in addition

$\rm log_{7} 98$ = $\rm log_{7} (49\times 2)$

= $\rm log_{7} 49 + \rm log_{7} 2$

Hence, the expression $\rm log_{7} 98$ using the product property is $\rm log_{7} 49 + \rm log_{7} 2$

Learn more on logarithm here:

brainly.com/question/12049968

algol [13]2 years ago

3 0

Answer:

log7 2 + log7 49

log7 49= 2

Step-by-step explanation:

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3 years ago

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acce

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at t= 0. the velocity is 30 mi/h.

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Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:

a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/ $h^{2}$

Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)

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3 years ago

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Sedbober [7]

Answer: $\bold{y=-\dfrac{1}{3}x-1}$

<u>Step-by-step explanation:</u>

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

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Next, find the midpoint of (4, 1) and (2, -5):

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Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

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