Question

Helppp quick pointsss

Answer 1

Answer:

1) The angle would be 150 degrees

a) coordinates would be ( $-\frac{\sqrt{3}}{2}$, $\frac{1}{2}$ )

b) Trigonometric ratios:

sin:  $\frac{1}{2}$

cos: $-\frac{\sqrt{3}}{2}$

tan: $-\frac{\sqrt{3}}{3}$

csc: 2,  

sec: $-\frac{2\sqrt{3}}{3}$

cot: $\sqrt{3}$

Explanation:

$\frac{17\pi }{6}$ simplifys to $\frac{5\pi }{6}$ which has a reference angle of $\frac{\pi }{6}$. We can take the coordinates of $\frac{\pi }{6}$ and make the x value negative to find the correct coordiantes. Then, using those coordinates, plug the into the trigonomic equations.

For example, sin in opposite/hypotenuse. So sin = 1/2 divided by 1. Then you can find the rest of the equations that way.

cos= adjacent/hypotenuse

tan= sin/cos

csc= hypotenuse/opposite

sec= hypotenuse/adjacent

cot= cos/sin