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3 years ago

Please answer this correctly

Mathematics

2 answers:

Lynna [10]3 years ago

8 0

Answer:

<h2><em><u>4/5 is the answer.</u></em></h2>

Step-by-step explanation:

<h2><em><u>Facts!</u></em></h2>

This is because 5 is odd and greater than 3.

Also. 4 is greater than 3.

After that, the other odd numbers are 1 and 3

So the numbers are 1, 3, 4, and 5.

So 4 out of 5 numbers are counted in the circle.

In this way 4/5 is the answer.

<h2><em><u>4/5 is the answer.</u></em></h2><h2><em><u></u></em></h2>

<em><u>Hope this helped!</u></em>

<em><u>Kavitha</u></em>

mr Goodwill [35]3 years ago

4 0

Answer:

4/5 chance

Step-by-step explanation:

There are 4 numbers that fit the rule, 1, 3, 4, 5, since all of them are either odd or greater than 3. There will be a 4/5 chance of picking one.

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3 years ago

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Step-by-step explanation:

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3 years ago

At the center of espionage in Kznatropsk one is thinking of a new method for sending Morse telegrams. Instead of using the tradi

alexgriva [62]

Answer:

It takes less time sending 5 letters the traditional way with a probability of 36.7%.

Step-by-step explanation:

First we must take into account that:

- The traditional method is distributed X ~ Poisson(L = 1)

- The new method is distributed X ~ Poisson(L = 5)

$P(X=x)=\frac{L^{x}e^{-L}}{x!}$

Where L is the intensity in which the events happen in a time unit and x is the number of events.

To solve the problem we must calculate the probability of events (to send 5 letters) in a unit of time for both methods, so:

- For the traditional method:

$P(X=5)=\frac{1^{5}e^{-1}}{1!}\\\\P(X=5) = 0.367$

- For the new method:

$P(X=5)=\frac{5^{5}e^{-5}}{5!}\\\\P(X=5) = 0.175$

According to this calculations we have a higher probability of sending 5 letters with the traditional method in a unit of time, that is 36.7%. Whereas sending 5 letters with the new method is less probable in a unit of time. In other words, we have more events per unit of time with the traditional method.

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3 years ago