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3 years ago

A rectangular cake measures 12 inches wide, 15 inches long, and 4 inches high.

Mathematics

1 answer:

V125BC [204]3 years ago

8 0

Answer:

B. 180

Step-by-step explanation:

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Using ratio pleases help i´m stuck i need #5 for one side 1-5 for the other

Fudgin [204]

How did you put multiple pictures on this app? i can’t figure how to

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3 years ago

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MAVERICK [17]

Answer:

$\sf x =\dfrac{2}{3}$

Explanation:

$\sf \rightarrow \dfrac{x+1}{2} = \dfrac{7x-3}{2}$

cross multiply

$\sf \rightarrow 2(x+1) = 2(7x-3)$

divide both sides by 2

$\sf \rightarrow x + 1 = 7x-3$

isolate variables

$\sf \rightarrow x -7x = -3-1$

simplify

$\sf \rightarrow -6x = -4$

divide both sides by -6

$\sf \rightarrow \dfrac{-6x}{-6} = \dfrac{-4}{-6}$

simplify

$\sf \rightarrow x =\dfrac{2}{3}$

4 0

1 year ago

Read 2 more answers

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago

This week beth made 10 more then twice the number of cookies she made last week,x. Which expression represents the total numbwr

Lapatulllka [165]

2x + 10 is the answer to the question

7 0

3 years ago

A bicycle rider increases his speed from 5 m/s to 15 m/s in 10 seconds

valentina_108 [34]

To find the acceleration of the bicycle rider, we are going to use the acceleration formula: $a= \frac{v_{f}-v_{i}}{t}$
where
$a$ is the acceleration
$v_{i}$ is the initial speed
$v_{f}$ is the final speed
$t$ is the time

We know from our problem that increases his speed from 5 m/s to 15 m/s in 10 seconds, so his initial speed is 5 m/s and his final speed is 15 m/s; therefore, $v_{i}=5$ , $v_{f}=15$ , and $t=10$ . Lets replace those values in our formula:
$a= \frac{v_{f}-v_{i}}{t}$
$a= \frac{15-5}{10}$
$a= \frac{10}{10}$
$a=1$

We can conclude that the acceleration of the bicycle rider 1 m/s^2

4 0

3 years ago