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Serga [27]
2 years ago
9

How do you describe the solution set to a system of linear inequalities?

Mathematics
1 answer:
Tatiana [17]2 years ago
6 0

Answer:

How do you describe the solution set to a system of linear inequalities?

Step-by-step explanation:

The solutions of a system of linear inequalities are all the ordered pairs that make all the inequalities in the system true.

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If the minute hand has turned 3/4 of the way around the face, it is equal to 45 minutes. (45/60)
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Please answer this multiple choice question for 30 points and brainliest!!
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Answer:

  B.  s = 0.85r

Step-by-step explanation:

The sale price is 15% off the regular price. In equation form, that is ...

  s = r - 15%×r

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The equation that can be used to calculate the sale price is <em>s = 0.85r</em>.

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3 years ago
Which is a factor of 6x2y + 8x2 − 30y − 40?
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<span>6x^2y + 8x^2 − 30y − 40
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3 years ago
A certain change in a process for manufacture of component parts is being considered. Samples are taken using both the existing
Katyanochek1 [597]

Answer:

a) The confidence interval is 0.00\leq\pi_1-\pi_2\leq0.02.

Step-by-step explanation:

We have to calculate a confidence interval (CI) of a difference of proportions.

For the existing procedure, the proportion is:

p_1=75/1500=0.05

For the new procedure, the proportion is:

p_2=80/2000=0.04

To calculate the CI, we need to estimate the standard deviation

s=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2} }\\\\s=\sqrt{\frac{0.05(1-0.05)}{1500} +\frac{0.04(1-0.04)}{2000} }=\sqrt{ 0.000032 + 0.000019 }=\sqrt{  0.000051 }\\\\s=0.007

For a 90% CI, the z-value is 1.64.

Then, the CI is:

(p_1-p_2)-z*\sigma \leq\pi_1-\pi_2\leq(p_1-p_2)+z*\sigma \\\\(0.05-0.04)-1.64*0.007\leq\pi_1-\pi_2\leq(0.05-0.04)+1.64*0.007\\\\0.01-0.01\leq\pi_1-\pi_2\leq0.01+0.01\\\\0.00\leq\pi_1-\pi_2\leq0.02

6 0
3 years ago
Pls hurry I’m being timed
nevsk [136]

Answer:

b

Step-by-step explanation:

I hope this helps and have a nice day

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3 years ago
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