Using the monthly payments formula, it is found that a car with a value of at most $25,293.
It is given by:
In which:
In this problem, we have that the parameters are given as follows:
A = 400, n = 70, r = 0.035.
Hence:
r/12 = 0.035/12 = 0.002917.
Then we have to solve for P to find the maximum value of the car.
P = $25,293.
More can be learned about the monthly payments formula at brainly.com/question/26267630
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Step-by-step explanation:
x-5 < -3
or, x < -3 +5
or, x < 2
Now,
x +8 >2
or, x >2 - 8
or, x >-6
Answer:
$9000
I=?
p=$300
R=5*1/100
T=6
I=P*R*T
$300*5/100*6
=$9000
ven numbers always end with a digit of 0, 2, 4, 6 or 8.
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30 are even numbers.
Odd numbers always end with a digit of 1, 3, 5, 7, or 9.
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 are odd numbers.
yes