Answer:
Kobe traveled a distance of 172.80 ft
Step-by-step explanation:
Given;
number of rotations of the bike, n = 20 rotations
diameter of the bike, d = 2.75 feet
radius of the bike, r = d/2 = 1.375 ft
Circumference of the bike wheel is given by;
D = 2πr
D = 2π(1.375 ft)
D = 8.641 ft
1 complete rotation = 8.641 ft
20 complete rotations = ?
= 20 x 8.641
= 172.82 ft
= 172.80 ft
Therefore, Kobe traveled a distance of 172.80 ft
