Question

A survey is taken among customers of a fast-food restaurant to determine preference for Hamburger and Cheeseburger. Of 180 respondents selected 90 were children and 90 were adults. 120 preferred Hamburger and 60 Cheeseburger. 40 of children preferred Hamburger. We randomly choose an individual. What is the probability this individual is a child? If the chosen person is an adult, what is the probability to prefer Cheeseburger? What is the probability to be a child or to prefer Cheeseburger?
a.1/2, 1/9, 5/9
b.1/2, 1/9, 5/18
c.1/3, 1/2, 1/9
d.1/2, 1/2, 5/18
e.1/2, 1/2, 5/9
If you can show me the solve step by step, thanks a lot

Answer 1

Using it's concept, it is found that the probabilities are given as follows:

a.1/2, 1/9, 5/9.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, 90 out of 180 individuals are children, hence the probability is given by:

p = 90/180 = 1/2.

Out of 90 adults, 60 - 50 = 10 preferred cheeseburgers, hence the probability is given by:

p = 10/90 = 1/9.

Of the 180 individuals, 90 are children, and 10 are adults who prefer cheeseburgers, hence the probability is given by:

p = 100/180 = 10/18 = 5/9.

Hence option a is correct.

More can be learned about probabilities at brainly.com/question/14398287

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