S/g=7/5, s=7g/5
s=g if s-30=g+30 using s found above...
7g/5 -30=g+30
(7g-150)/5=g+30
7g-150=5g+150
2g=300
g=150, and since s=7g/5, s=210
So Simon started with 210 pencils and Greg started with 150 pencils.
1:5
Steps:
1. Add all the numbers
2. Take Derek’s number of votes and turn step 1’s answer and Derek’s number of votes into a ration:
3. You will now have 36:180
4. Simplify by a number they both share (36).
5. Your new simplified answer would be 1:5.
You can use the Pythagorean theorem, a^2+b^2=c^2, to solve this.
b= square-root of (c^2)-(a^2)
b= square-root of (9^2)-(2^2)
b= 8.77.... which in the exact form is square root of 77.
To calculate amount accrued after a given period of time we use the compound interest formula: A= P(1+r/100)∧n where A i the amount, P is the principal amount, r is the rate of interest and n is the interest period.
In the first part; A= $ 675.54, r= 1.25% (compounded semi-annually) and n =22 ( 11 years ), hence, 675.54 = P( 1.0125)∧22
= 675.54= 1.314P
P= $ 514.109 , therefore the principal amount was $ 514 (to nearest dollar)
Part 2
principal amount (p)= $ 541, rate (r) = 1.2 % (compounded twice a year thus rate for one half will be 2.4/2) and the interest period (n)= 34 (17 years×2)
Amount= 541 (1.012)∧34
= 541 ×1.5
= $ 811.5
Therefore, the account balance after $ 811.5.
