Answer: Range is something
Step-by-step explanation:
I think the answer to this question is option D
Divide the current year by the previous year then multiply it by 100.
The margin of error of the random selection is 0.29
The given parameters are:
--- the sample size
--- the standard deviation
--- the mean
--- the confidence level.
The margin of error (E) is calculated as follows:
![E = z \times \sqrt{\frac{\sigma^2}{n}}](https://tex.z-dn.net/?f=E%20%3D%20z%20%5Ctimes%20%5Csqrt%7B%5Cfrac%7B%5Csigma%5E2%7D%7Bn%7D%7D)
So, we have:
![E = z \times \sqrt{\frac{3.2^2}{320}}](https://tex.z-dn.net/?f=E%20%3D%20z%20%5Ctimes%20%5Csqrt%7B%5Cfrac%7B3.2%5E2%7D%7B320%7D%7D)
![E = z \times \sqrt{\frac{10.24}{320}}](https://tex.z-dn.net/?f=E%20%3D%20z%20%5Ctimes%20%5Csqrt%7B%5Cfrac%7B10.24%7D%7B320%7D%7D)
The z-value for 90% confidence level is 1.645.
Substitute 1.645 for z
![E = 1.645 \times \sqrt{\frac{10.24}{320}}](https://tex.z-dn.net/?f=E%20%3D%201.645%20%5Ctimes%20%5Csqrt%7B%5Cfrac%7B10.24%7D%7B320%7D%7D)
![E = 1.645 \times \sqrt{0.032}](https://tex.z-dn.net/?f=E%20%3D%201.645%20%5Ctimes%20%5Csqrt%7B0.032%7D)
Take square roots
![E = 1.645 \times 0.1789](https://tex.z-dn.net/?f=E%20%3D%201.645%20%5Ctimes%200.1789)
Multiply
![E = 0.2943](https://tex.z-dn.net/?f=E%20%3D%200.2943)
Approximate
![E = 0.29](https://tex.z-dn.net/?f=E%20%3D%200.29)
Hence, the margin of error is 0.29
Read more about margin of error at:
brainly.com/question/14396648