Since you know that a square has 4 equal sides then you know the small squares are 4cm on all sides and the big squares are 9cm on all sides.
If 2 and a partial sm sq are next to a 9cm sq then knowing 4*2=8 you can figure out that the other square is split as 1cm and 3cm(1+3=4), 3cm of which is lined up with the width (4cm)of another sm sq which would equal 7cm, these 2 sm sqs line up with the unknown sq whose sides would in turn also be 7cm.
A=l*w, 7*7=49
Answer:Area=49cm^2
Answer:
24
Step-by-step explanation:
8= 8, 16 ,24 , 32 , 40, 48, 56, 64, 72, 80
6= 6, 12, 18, 24, 30, 36, 42, 48, 54, 50
Answer:
x ≈ 3.9
Step-by-step explanation:
Call the segment shared by the two triangle "y". The Pythagorean theorem tells you ...
sum of squares of sides = square of hypotenuse
y² +6² = 10²
x² +7² = y²
Substituting for y² using the second equation, we get ...
x² +7² +6² = 10²
x² = 10² -7² -6² = 100 -49 -36 = 15
Taking the square root, we find ...
x = √15 ≈ 3.9
we name bases k , k+6. so
area: 96= (k + k+6).8/2
=> 2k+6= 24 => k=9
Same cause school kinda slow bsndndndndnndnfnfnfnfn sorry I need the points
