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s344n2d4d5 [400]
1 year ago
8

If a= 2x - 3 and b= 2x+5 find the value of a+b help pleaseeee i would really appreciate

Mathematics
2 answers:
Goshia [24]1 year ago
6 0

Answer:

4x+2

Step-by-step explanation:

a= 2x - 3 and b= 2x+5

a+b = 2x-3 + 2x+5

Combine like terms

a+b = 4x+2

Mamont248 [21]1 year ago
5 0

Answer:

a + b = 4x + 2

Step-by-step explanation:

a = 2x - 3

b = 2x + 5

a + b = (2x-3) + (2x+5)

a + b = 2x + 2x - 3 + 5

a + v = 4x + 2

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Five times the sum of a number and 3 is the same as 3 multiplied by 1 less than twice the number ​
Aneli [31]

Answer:-2

Step-by-step explanation:

(n + 3) 5 = 3 x 1 - n

distribute so 5n + 15= 3 - n

subtract three from both sides

5n - 12 = -n

subtract 5n from both sides

12 = −6n

Divide both sides by -6

n=-2

7 0
3 years ago
Jimmy spent 45 minutes to finish his homework. There are 20 problems. What is the average amount of time he spends to finish eac
nexus9112 [7]
The average is (time)/(number of problems)=(45/60)/20=(3/4)/20=3/80  hours per problem. In minutes, the answer would be 3/80*60=9/4 minutes per problem.
6 0
3 years ago
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2 years ago
Jacob transformed quadrilateral FGHJ to F'G'H'J'.
Rudik [331]

Answer:

A. Reflection across the line x = 1

Step-by-step explanation:  

Please find the attachment.

We have been given that Jacob transformed quadrilateral FGHJ to F'G'H'J'.  We are asked to find which transformation Jacob used to reflect FGHJ to F'G'H'J'.

Since we know that while reflecting a figure, the line of reflection will lie between the original figure and reflected figure. Each point of the reflected figure will have the same distance from the line of reflection as the corresponding point of the original figure.              

Now let us see our given choices one by one.

A. Reflection across the line x = 1.

Upon looking at point G and G' we can see that both points are equidistant (2 units) from the line x=1. Other corresponding points of both quadrilaterals are also equidistant from line x=1, therefore, Jacob used the reflection across the line x=1 to transform quadrilateral FGHJ to F'G'H'J'.

B. Reflection across the line y = 1 .      

If Jacob had reflected quadrilateral across line y=1, the points of quadrilateral F'G'H'J' will lie in second and third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option B is not a correct choice.

C. Reflection across the line y-axis.

If Jacob had reflected quadrilateral across y-axis, the coordinates of points of quadrilateral F'G'H'J' will be G'(1,4), H'(1,2), J'(4,0) and F'(2,5). Therefore, option B is not a correct choice.

D.  Reflection across the x -axis.

If Jacob had reflected quadrilateral across x-axis, the points of quadrilateral F'G'H'J' will lie in third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option D is not a correct choice.

3 0
3 years ago
At the county fair, Darius can purchase 3 candy apples and 4 bags of peanuts for $11.33. He can purchase 9 candy apples and 5 ba
Ksenya-84 [330]
Let c represents the cost of a candy apple and b represents the cost of a bag of peanuts.

Darius can purchase 3 candy apples and 4 bags of peanuts. So his total cost would be 3c + 4b. Darius can buy 3 candy apples and 4 bags of peanuts in $11.33,so we can write the equation as: 

3c + 4b = 11.33   (1)

Darius can purchase 9 candy apples and 5 bags of peanuts. So his total cost would be 9c + 5b. Darius can buy 9 candy apples and 5 bags of peanuts in $23.56,so we can write the equation as: 

9c + 5b = 23.56   (2)

<span>Darius decides to purchase 2 candy apples and 3 bags of peanuts. The total cost in this case will be 2c + 3b. To find this first we need to find the cost of each candy apple and bag of peanuts by solving the above two equations.

Multiplying equation 1 by three and subtracting equation 2 from it, we get:

3(3c + 4b) - (9c + 5b) = 3(11.33) - 23.56

9c + 12b - 9c - 5b = 10.43

7b = 10.43

b = $1.49

Using the value of b in equation 1, we get:

3c + 4(1.49) = 11.33

3c = 5.37

c = $ 1.79

Thus, cost of one candy apple is $1.79 and cost of one bag of peanuts is $1.49.

So, 2c + 3b = 2(1.79) + 3(1.49) = $ 8.05

Therefore, Darius can buy 2 candy apples and 3 bags of peanuts in $8.05</span>
3 0
3 years ago
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