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2 years ago

Can anyone help me???

Mathematics

1 answer:

natita [175]2 years ago

5 0

Answer:

principal (p)=$1300

Interest (I) =$28.67

Time( T) = 1 year

R=?

we have,

R = I*100/T*R

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

School pennants cost $18 each. Ms.Lee says she will pay $146 for 7 pennants. Is her answer reasonable?

crimeas [40]

Well, all we have to do to figure out if Ms. Lee’s offer is reasonable is multiply the unit price ($18) by 7

18 x 7 = 126

Since she offered $146, she could actually purchase 8 pennants for $144

Therefore, her answer wouldn’t be reasonable

Hope this helps you

Brainliest would be appreciated!

-AaronWiseIsBae

3 0

3 years ago

At the movie theater, childs admission is $6.10. Adult admission is $9.40. On Tuesday four times as many adult tickets as child

Harlamova29_29 [7]

Answer:

The number of children's tickets sold was 27

Step-by-step explanation:

Let

x ----> the number of children's tickets sold

y ----> the number of adult's tickets sold

we know that

$6.10x+9.40y=1,179.90$ ----> equation A

$y=4x$ ----> equation B

Solve the system by substitution

Substitute equation B in equation A

$6.10x+9.40(4x)=1,179.90$

solve for x

$6.10x+37.6x=1,179.90$

$43.7x=1,179.90$

$x=27$

therefore

The number of children's tickets sold was 27

8 0

3 years ago

What numbers are greater than 20 that has 9 as a factor

OLga [1]

Any of 9's multiples besides 9 and 18 will work.

So: 27, 35, 45, 54 ,63, 72, 81, 90, 99, 108, 117, 126, 135, and so on

4 0

3 years ago

Read 2 more answers

What is 14/4y + 4/2=3y-3

OverLord2011 [107]

Answer:

-10

Step-by-step explanation:

Solve for y by simplifying both sides of the equation, then isolating the variable

4 0

3 years ago