1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ELEN [110]
2 years ago
12

Which point is located at (4, -2, -3)? O point A O point B O point C O point D

Mathematics
1 answer:
iren2701 [21]2 years ago
8 0

Answer:

Option 2: Point B

It is the only point where x = 4, y = -2, and z = -3.

You might be interested in
A cross section is the intersection of which two elements?
viva [34]
The answer is:

A solid and a plane.
4 0
4 years ago
Read 2 more answers
Can someone help me out on these 2 geometry questions pls? ASAP!!!
Katena32 [7]

<u>Question 2</u>

1) \overline{PR} \perp\overline{QS}, \overline{PQ} \cong \overline{PS} (given)

2) \overline{PR} \cong \overline{PR} (reflexive property)

3) \angle PRQ, \angle PRS are right angles (perpendicular lines form right angles)

4) \triangle PRQ, \triangle PRS are right triangles (a triangle with a right angle is a right triangle)

5) \triangle PRQ \cong \triangle PRS (HL)

<u>Question 3</u>

1) \angle C is a right angle, \overline{AC} \cong \overline{AE}, \overline{DE} \perp \overline{AB} (given)

2) \angle DEA is a right angle (perpendicular lines form right angles)

3) \triangle ACD, \triangle DAE are right triangles (a triangle with a right triangle is a right angle)

4) \overline{AD} \cong \overline{AD} (reflexive property)

5) \triangle ACD \cong \triangle AED (HL)

6) \angle CAD \cong \angle DAE (CPCTC)

7) \overline{AD} bisects \angle BAC (if a segment splits an angle into two congruent parts, it is an angle bisector)

6 0
2 years ago
Maria placed the letters PROBABILITY into a bag. She will draw a letter, keep it, and draw a second letter. What
Yakvenalex [24]

Answer:

I think it’s 2/11

Step-by-step explanation:

3 0
3 years ago
Write an equation that expresses the following relationship.
AlexFokin [52]

The equation become u = k p^2 / d.

According to the statement

we have given that some conditions for the equations and we have t make the equation from the given equations.

So, For this purpose, we have given that

The equation in which u is varies directly with the square of p and inversely with d and use the k as the constant of proportionality.

So, From all these above the equation will become is

u = k p^2 / d

In latex form the equation write as :

u =  \frac{kp^{2}}{d}

In this equation all the given conditions are applicable.

So, The equation become u = k p^2 / d

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Write an equation that expresses the following relationship. u varies directly with the square of p and inversely with d In your equation, use k as the constant of proportionality.

Learn more about equations here

brainly.com/question/2972832

#SPJ1

7 0
2 years ago
Answer to the problem
lara31 [8.8K]
That would be C Answer
6 0
3 years ago
Other questions:
  • If 2 x + 3+ 7x = -24 what is the value of x​
    5·1 answer
  • At the market you purchase some apples and oranges. There were 12 items purchased. You buy twice as many apples as oranges. (5 p
    7·2 answers
  • There are 40 students in a class and 35 of them are going on a field trip. What percent of the class is not going on the field t
    14·1 answer
  • PLEASE SHOW ME HOW TO SOLVE THESE QUESTIONS ASAP PLEASE!!
    12·2 answers
  • A coffee shop s ends $408 for an order of 17 cases of paper cups.
    14·1 answer
  • Solve pleaseeeeeeeeeeeeeeeeeeeeeeee
    10·2 answers
  • Create your own data set (one not used in the lesson) and find the interquartile range. You can make up the data, but have a rea
    7·1 answer
  • Is this right ? if not please help me !
    6·2 answers
  • Question is attached!​
    7·2 answers
  • Select all ordered pairs that satisfy the function
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!