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Anestetic [448]
4 years ago
7

The function ff is an odd function that contains the points (0, 0)(0,0), (1, -3)(1,−3), (2, -2)(2,−2), and (3, 1)(3,1). The orde

red pair (-3, y)(−3,y) is also on the graph of y=f(x)y=f(x) for what value of yy
Mathematics
1 answer:
IRINA_888 [86]4 years ago
6 0

Answer:

  y = -1

Step-by-step explanation:

For an odd function, f(-x) = -f(x). That means f(-3) = -f(3) = -1. If the point (3, 1) is on the graph, so is the point (-3, -1).

If (-3, -1) = (-3, y), then y = -1.

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Qual son los pares de 48
lyudmila [28]

Answer:

1

2  

3  

4  

6  

8  

12  

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24  

48

Step-by-step explanation:

Es un proceso de dos pasos para crear todos los pares de factores de 48: Primero, enumeramos todos los factores de 48. Luego, combinamos todas las diferentes combinaciones de factores para obtener todos los pares de factores de 48.

Todas las diferentes combinaciones de pares de los factores de 48 anteriores son los pares de factores de 48. A continuación se muestra la lista de todos los pares de factores de 48. Como puede ver, todos los pares de factores de 48 equivalen a 48 cuando los multiplica

It is a two-step process to create all the Factor Pairs of 48: First, we list all the factors of 48. Then, we pair all the different combinations of factors to give you all the Factor Pairs of 48.

All the different pair combinations from the factors of 48 above are the Factor Pairs of 48. Below is the list of all the Factor Pairs of 48. As you can see, all Factor Pairs of 48 equal 48 when you multiply them together.

8 0
3 years ago
X - 8 + (-8x) - 15 when x = -9
Irina-Kira [14]

Answer:

40

Step-by-step explanation:

Plug x=-9 in. -9-8+(-9×(-8)) -15=-17+72-15=-17+72-15=40. I hope this helped!

8 0
4 years ago
Read 2 more answers
Identify weather the sentence below is active can be rewritten in active voice or cannot be rewritten the fire was set some time
bazaltina [42]
The sentence cannot be written in active voice. the sentence would not make anu sence. the store robbed just after midnight is written in active voice and it does not make sense
8 0
3 years ago
Fibonacci posed the following problem: Suppose that rabbits live forever and that every month each pair produces a new pair whic
docker41 [41]

Answer:

Let f_n be the number of rabbit pairs at the beginning of each month. We start with one pair, that is f_1 = 1. After one month the rabbits still do not produce a new pair, which means f_2 = 1. After two months a new born pair appears, that is f_3 = 2, and so on. Let now n \geq 3 be any natural number. We have that f_n is equal to the previous amount of pairs f_n-1 plus the amount of new born pairs. The last amount is f_n-2, since any two month younger pair produced its first baby pair. Finally we have  

f_1 = f_2 = 1,f_n = f_n-1 + f_n-2 for any natural n  \geq 3.  

5 0
4 years ago
Hiii y’all is this answer correct or is it 3/5?
viva [34]
It’s 3/5 since it should be adjacent/hypotenuse and 4 is the opposite
4 0
3 years ago
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