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1 year ago

11

Can someone help me with this problem? Thank you!

1 answer:

timofeeve [1]1 year ago

5 0

Answer:

To find the area of a square, multiply the 2 sides by each other (all sides are equal)

S=14×14=196

196m^2

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If there are 4boys and 2girls in a family, what is the ratio of boys in the family to children in the family?

BARSIC [14]

Assuming the 4 girls and 2 boys are all children, the ratio of boys to toal children is 2 to 6. This can simplify to 1 to 3.
Final answer: 1 to 3

3 0

2 years ago

A population of bacteria is growing according to the exponential model P = 100e.70t, where P is the number of colonies and t is

Reika [66]

T=(log(300÷100)÷log(e))÷0.7
T=1.6

6 0

3 years ago

Read 2 more answers

Please help (question is in the attachment) :(

Kitty [74]

Answer:

The answer is D

Step-by-step explanation:

Because both when we multiply we will get the same answer

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2 years ago

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What are the primary differences between the different 1040 forms?

Rina8888 [55]

Two of the forms used for filing individual federal income tax returns<span> are IRS </span>Form 1040A<span> and IRS Form </span>1040EZ. Trhe third one is the complex IRS Form 1040. <span>Form 1040EZ is the briefest version of the 1040. You can't itemize deductions or claim any adjustments to income or tax credits except for the </span>Earned Income Credit<span>, and you can't have any income from self-employment, </span>alimony<span>, dividends or </span>capital gains<span>. </span><span>

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8 0

3 years ago

Working together, it takes Sam, Jenna, and Francisco two hours to paint one room. When Sam works alone, he can paint one room in

lutik1710 [3]

Answer: 12 hours

Step-by-step explanation:

Given : Working together, it takes Sam, Jenna, and Francisco two hours to paint one room.

When Sam works alone, he can paint one room in 6 hours. When Jenna works alone, she can paint one room in 4 hours.

Let 't' be the time taken by Francisco to paint one room on his own.

Then , we have

Rate of work of Sam +Rate of work of Jenna + Rate of work of Francisco =Rate of work they all do together

$\dfrac{1}{6}+\dfrac{1}{4}+\dfrac{1}{t}=\dfrac{1}{2}$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{1}{6}+\dfrac{1}{4})$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{4+6}{24})$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-\dfrac{10}{24}$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-\dfrac{5}{12}$

i.e. $\dfrac{1}{t}=\dfrac{6-5}{12}$

i.e. $\dfrac{1}{t}=\dfrac{1}{12}$

i.e. t= 12

Hence, Francisco would take 12 hours to paint one room on his own.

8 0

3 years ago