Try this solution:1. to make up the characteristic equation:α²+5α=0;
![\left[\begin{array}{ccc} \alpha=0 \\ \alpha =-5\\\end{array}](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Calpha%3D0%20%5C%5C%20%5Calpha%20%3D-5%5C%5C%5Cend%7Barray%7D)
2. to make up the final answer:y=C₁+C₂e⁻⁵ˣ
add them both then you get the awnser if the four is not a negative. if the four is a negative use division.
Answer:
The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = 1/5|h - 240| - 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet).
Step-by-step explanation:
Answer:
2x + y = 5
y = 4x – 1
Substitute (2, 1) into system, then:
2x + y = 5 => 2 x 2 + 1 = 5 => 5 = 5 (satisfied)
y = 4x– 1 => 4 x 2 - 1 = 1 => -7 = 1 (not satisfied)
=> Option 3 is correct.
Hope this helps!
:)
Answer:
a)
b) ![P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668](https://tex.z-dn.net/?f=P%28X%3E%202%29%3D1-P%28X%5Cleq%202%29%3D1-%5B0.0211%2B0.0995%2B0.211%5D%3D0.668)
c)
Step-by-step explanation:
1) Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
2) Solution to the problem
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Part a
Part b
![P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]](https://tex.z-dn.net/?f=P%28X%3E%202%29%3D1-P%28X%5Cleq%202%29%3D1-%5BP%28X%3D0%29%2BP%28X%3D1%29%2BP%28X%3D2%29%5D)
![P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668](https://tex.z-dn.net/?f=P%28X%3E%202%29%3D1-P%28X%5Cleq%202%29%3D1-%5B0.0211%2B0.0995%2B0.211%5D%3D0.668)
Part c