A = 3 b = -16 and c = 2
the radicand would be
sq root (b^2 -4*a*c) =
sq root (256 -4*3*2) =
sq root (232)
So the roots will be real and not complex.
If i’m not mistaken, it should be 2/10, or 20/100. and it’s percentage would be 20%
Answer:
y = 0.5 (x^2 -2x + 16) has a y-intercept of 8.
Step-by-step explanation:
The x-coordinate of every y-intercept is zero. To determine which of the four quadratics given here has a y-intercept of 8, we need only substitute 0 for x in each; if the result is 8, we've found the desired quadratic.
O y = 0.5(x + 2)(x + 4) becomes y = 0.5(2)(4) = 4 (reject this answer)
O y = 0.5 (x - 2)(x + 8) becomes y = 0.5(-2)(8) = -8 (reject)
O y = 0.5(x2 -2x - 16) becomes y = 0.5(-16) = -8 (reject)
<em>O y = 0.5 (x2 -2x + 16) becomes y = 0.5(16) = 8 This is correct; that '8' represents the y-intercept (0, 8).</em>
Are these true and false? I think it's true for both
Area = 4 cm * 8 cm = 32 cm²
