Question

The sum of two numbers is 39.Three times the smaller number exceeds the larger number by 81. Find the numbers

Answer 1

Let smaller no be x and bigger be y

• x+y=39--(1)
• 3x=y+81
• y=3x-81
• y=3(x-27)--(2)

Put it in eq(1)

• x+3(x-27)=39
• x+3x-81=39
• 4x=81+39
• 4x=120
• x=30

Now

• x+y=39
• y=39-30
• y=9

The numbers are 9 and 30