Answer= x^2-4
I hope this helps.
Answer:
(i) ∠ABH = 14.5°
(ii) The length of AH = 4.6 m
Step-by-step explanation:
To solve the problem, we will follow the steps below;
(i)Finding ∠ABH
first lets find <HBC
<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)
46° + <HBC + 90 = 180°
<HBC+ 136° = 180°
subtract 136 from both-side of the equation
<HBC+ 136° - 136° = 180° -136°
<HBC = 44°
lets find <ABC
To do that, we need to first find <BAC
Using the sine rule
= 
A = ?
a=6.9
C=90
c=13.2
= 
sin A = 6.9 sin 90 /13.2
sinA = 0.522727
A = sin⁻¹ ( 0.522727)
A ≈ 31.5 °
<BAC = 31.5°
<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)
31.5° +<ABC + 90° = 180°
<ABC + 121.5° = 180°
subtract 121.5° from both-side of the equation
<ABC + 121.5° - 121.5° = 180° - 121.5°
<ABC = 58.5°
<ABH = <ABC - <HBC
=58.5° - 44°
=14.5°
∠ABH = 14.5°
(ii) Finding the length of AH
To find length AH, we need to first find ∠AHB
<AHB + <BHC = 180° ( angle on a straight line)
<AHB + 46° = 180°
subtract 46° from both-side of the equation
<AHB + 46°- 46° = 180° - 46°
<AHB = 134°
Using sine rule,
= 
AH = 13.2 sin 14.5 / sin 134
AH≈4.6 m
length AH = 4.6 m
Answer:
i think 120, im not quite sure, im not the best at this
Step-by-step explanation:
Answer:
1. ║u-z║= 5.66
2.║v-w║=6.0
3. ║w-u║=6.08
4.║v-u║=7.81
Step-by-step explanation:
The vectors are given as;
u = <-1, -3>, v = <5,-8>, w = <5, -2>, and z = <3, 1>.
To find the magnitude of the vectors;
1. ║u-z║
<-1 - 3> = <-4 and < -3 - 1> = <-4
║<-4,-4> ║= √{ -4²+-4²} = √32 = 5.66
2.║v-w║
<5,-8> - <5,-2>
<5-5> , <-8--2>
<0,-6>
║<0,-6>║= √{0²+ -6²} = √36 = 6
3. ║w-u║
<5,-2> - <-1,-3>
<5--1> , <-2--3>
<6,1>
║6,1║= √{6²+1²} = √36+1 = √37 = 6.08
4.║v-u║
<5,-8> - <-1,-3>
<5--1> , <-8--3>
< 6 , -5 >
║6,-5║= √{6²+-5²} = √36+25 =√61 = 7.81