The answer is 7. That's the answer
Answer:
This cannot be solved unless I have the coordinate for triangle "abc"
Step-by-step explanation:
Once I have the coordinates for triangle "abc", I can solve to find out where triangle "A'B'C" is
If you would like to solve the system of equations, you can do this using the following steps:
5p - 3r = 1 /*2
8p + 6r = 4
__________
10p - 6r = 2
<span>8p + 6r = 4
</span>__________
10p - 6r + 8p + 6r = 2 + 4
18p = 6
p = 6/18
p = 1/3
<span>5p - 3r = 1
</span>5 * 1/3 - 3r = 1
5/3 - 3r = 1
5/3 - 1 = 3r
5/3 - 3/3 = 3r
2/3 = 3r
r = 2/9
(p, r) = (1/3, 2/9)
The correct result would be <span>(1/3, 2/9)</span>.
Answer:
Presumably you're solving for x here? Without further information we'll assume that.
With that in mind, x is approximately equal to 0.86 and -0.46
Step-by-step explanation:
Let's start by putting it in the usual ax² + bx + c format.

let's solve it. First we'll multiply both sides by five, making the first term a perfect square:

Now we'll add 11 to both sides:

Which makes the left side a perfect square:

And now we can solve for x:

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.
That gives us two answers:

Answer:
1,2
Step-by-step explanation:
3+-1=2
2/2=1
3+1=4
4/2=2