Answer:
96
Step-by-step explanation:
it 32 x 3
Complete Question
A population has a mean of 25, a median of 24, and a mode of 26. The standard deviation is 5. The value of the 16th percentile is _______. The range for the middle 3 standard deviation is _______.
Answer:
The value of the 16th percentile is 
The range for the middle 3 standard deviation is 
Step-by-step explanation:
From the question we are told that
The mean is 
The median is 
The mode is 
The standard deviation is 
Generally the 16th percentile is mathematically represented as
![P(x)= P(\frac{X - \mu }{ \sigma } \le \frac{x- 25 }{5} ) = 0.16[/teGenerally [tex]\frac{X - \mu}{\sigma } = Z(The \ standardized \ value \ of \ X )](https://tex.z-dn.net/?f=P%28x%29%3D%20P%28%5Cfrac%7BX%20%20-%20%20%5Cmu%20%7D%7B%20%5Csigma%20%7D%20%20%20%5Cle%20%5Cfrac%7Bx-%2025%20%7D%7B5%7D%20%29%20%3D%200.16%5B%2Fte%3C%2Fp%3E%3Cp%3EGenerally%20%20%5Btex%5D%5Cfrac%7BX%20-%20%20%5Cmu%7D%7B%5Csigma%20%7D%20%20%3D%20%20Z%28The%20%20%5C%20%20standardized%20%5C%20%20value%20%5C%20of%20%20%5C%20X%20%20%29)
So

Now from the normal distribution table the z-score of 0.16 is
z = -1

=> 
=> 
=> 
=> 
The range for the middle 3 standard deviation is mathematically represented



Removed sugar is 3/8 and it is 5.81-3.8=2.01 kg
so 3/8 is 2.01 kg
full mass of sugar is 2.01:3*8=5.6 kg
so the mass of container is 5.81-5.6=0.21 kg
Answer: the mass of <span>empty container is 0.21kg</span>
The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.
<h3>Equation</h3>
Let
- Size of the first application = x
- Size of the second application= x - 3.45 mb
For instance,
if the size of the first application is 297 MB
Size of the second application= x - 3.45 mb
= 297 MB - 3.45 MB
= 293.55 MB
Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB
Learn more about equation:
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