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2 years ago

15

90 degress and 30 degrees what dose x=

1 answer:

lions [1.4K]2 years ago

4 0

Answer:

120

Step-by-step explanation: 90+30

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3 years ago

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Please Help Giving Brainliest!!!!! (05.06)Which net matches the solid figure shown below? A three-dimensional cube with a height

leva [86]

Answer:

A net is shown with 3 rectangles attached side by side all with width 8 centimeters and length of 7 centimeters. Attached to the middle rectangle above is a rectangle with same length and a width of 3 centimeters. Attached to the rectangle underneath are 2 more rectangles with the same length and widths of 8 centimeters and 3 centimeters.

Step-by-step explanation:

A net is a flat version of a three dimensional shape. Imagine that you have a tissue box. If you cut along the edges and laid out the pieces, you would have the net of the shape. The third choice gives the correct net that would fold back up to a rectangular solid with the given dimensions.

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3 years ago

Who wants to talk? I will give Brainliest to the first person!

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Answer:

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Step-by-step explanation:

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3 years ago

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If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .

ollegr [7]

Answer:

$2y^2-7y+6=0$

Step-by-step explanation:

We are given that $\alpha$ and $\beta$ are the zeroes of the polynomial $6y^2-7y+2$

$y^2-\frac{7}{6}y+\frac{1}{3}$

We have to find a quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ .

General quadratic equation

$x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes$

We get

$\alpha+\beta=\frac{7}{6}$

$\alpha \beta=\frac{1}{3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3$

Substitute the values

$y^2-(7/2)y+3=0$

$2y^2-7y+6=0$

Hence, the quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ is given by

$2y^2-7y+6=0$

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3 years ago

Write the standard equation of a circle with center (2, −5) and radius 16.

astra-53 [7]

The standard equation of circle when center is (h,k) and radius is 'r'

$\left ( x - h \right )^{2} + \left ( y - k \right )^{2} = r^{2}$

h = 2 and k = - 5, radius = 16

So equation of the circle is given by

$\left ( x - 2 \right )^{2} + \left ( y - (-5) \right )^{2} = 16^{2}$

$\left ( x - 2 \right )^{2} + \left ( y + 5) \right )^{2} = 256$

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4 years ago

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