<h3>
Answer: 5</h3>
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Work Shown:
x^2 - 5x + 1 = 0
x^2 + 1 - 5x = 0
x^2 + 1 = 5x
(x^2 + 1)/x = 5 .... where x is nonzero
(x^2)/x + (1/x) = 5
x + (1/x) = 5
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An alternative method involves solving the original equation using the quadratic formula. After you get the two roots x = p and x = q, you should be able to find that p + 1/p = 5 and also q + 1/q = 5 as well.
In this case,
p = (5 + sqrt(21))/2
q = (5 - sqrt(21))/2
The answers are (-3,-12), (-2,-10), (5,4)
Answer:
actually it is
Step-by-step explanation:
i skipped the whole question except the last sentence's few words
To solve for the value of x, you can simply add all of the values and expressions together and make it equal to 180 degrees, since the sum of all angles in a triangle add up to this amount.
Then we can solve for X, by algebra.
Answer: The probability of drawing a red marble the sixth time is 1/2
Step-by-step explanation:
Here is the complete question:
A box contains 10 red marbles and 10 green marbles. Sampling at random from the box five times with replacement, you have drawn a red marble all five times. What is the probability of drawing a red marble the sixth time?
Explanation:
Since the sampling at random from the box containing the marbles is with replacement, that is, after picking a marble, it is replaced before picking another one, the probability of picking a red marble is the same for each sampling. Probability, P(A) is given by the ratio of the number of favourable outcome to the total number of favourable outcome.
From the question,
Number of favourable outcome = number of red marbles =10
Total number of favourable outcome = total number of marbles = 10+10= 20
Hence, probability of drawing a red marble P(R) = 10 ÷ 20
P(R) = 1/2
Since the probability of picking a red marble is the same for each sampling, the probability of picking a red marble the sixth time is 1/2
