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sukhopar [10]
3 years ago
9

HELP!! Not hard, just confusing.. ΔABC is reflected across the x-axis and then translated 4 units up to create ΔA′B′C′. What are

the coordinates of the vertices of ΔA′B′C′ ?
Mathematics
1 answer:
allsm [11]3 years ago
8 0
The coordinates of the vertices of ΔABC are:A( x1, y1), B( x2, y2) and C( x3, y 3 ). After it is reflected across the x-axis, coordinates are ( x1, -y1), (x2, -y2), (x3, -y3). Finally, the coordinates of the vertices of ΔA´B´C´ after translation are: A´( x1, 4-y1), B´( x2, 4- y2), C´( x3, 4-y3 ) 
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PQRS is a trapezoid with a right angle. What are the coordinates of S
Brrunno [24]

Answer: (a, 0)

<u>Step-by-step explanation:</u>

Notice that S is on the x-axis, therefore the y-coordinate is "0".

Notice that S has the same x-value of R. The x-value of R is "a".

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3 years ago
What is the percent change from 36 to 63
viva [34]
Initial number = 36
Final number = 63
Change in number = 63 - 36
                               = 27
Percentage change = (27/36) * 100
                                 = (3/4) * 100
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So the percentage change from 36 to 63 is 75%. I hope the procedure for solving is absolutely clear for you to understand. In future you can attempt such problems by following the procedure shown and you will require no further help from outside. Just be careful about the numerator and the denominator.
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Please help will give brainlest
shtirl [24]

Answer:

18

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Here,

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A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

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3 years ago
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