Question

Which equation would have real zero(s) corresponding to the x-intercept(s) of the graph below?

Answer 1

Answer:

the first one listed (y = -$2^{x}$ + 4)

Step-by-step explanation:

a 0 at an x-intercept means that when plugging in that number, you get a 0 as a y-value.

So, the easiest method to use is to plug x=2 into each equation listed, because we can see that (2,0) is a point on this graph

if y= -$2^x$ + 4

y = -2² + 4

y = -4 + 4

y = 0

This means that this graph has corresponding real zero(s) to the function    y= $-2^x$ + 4

(I chose which graph to test by looking to see which option seemed right)