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nata0808 [166]
2 years ago
7

Which equation would have real zero(s) corresponding to the x-intercept(s) of the graph below?

Mathematics
1 answer:
hjlf2 years ago
7 0

Answer:

the first one listed (y = -2^{x} + 4)

Step-by-step explanation:

a 0 at an x-intercept means that when plugging in that number, you get a 0 as a y-value.

So, the easiest method to use is to plug x=2 into each equation listed, because we can see that (2,0) is a point on this graph

if y= -2^x\\ + 4

y = -2² + 4

y = -4 + 4

y = 0

This means that this graph has corresponding real zero(s) to the function    y= -2^x + 4

(I chose which graph to test by looking to see which option seemed right)

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