What is the answer i need answers now like right now

I need help thank you

Aleks [24]

Answer:

c)

Step-by-step explanation:

x - 2 ---------------> members in the band with the absentees.

So, x will give the number of members in the band

7 0

4 years ago

SNOW The first four snowfalls of the year in Shawnee's hometown measured 1.6 inches, 2.2 inches, 1.8 inches, and 1.4 inches. Use

wel

Answer:

The total amount of snow that fell is <u>7 inches</u>.

Step-by-step explanation:

Given:

The first four snowfalls of the year in Shawnee's hometown measured 1.6 inches, 2.2 inches, 1.8 inches, and 1.4 inches.

Now, to find the total amount of snow that fell.

Shawnee's hometown measured first four snowfalls of the year are:

1.6 inches, 2.2 inches, 1.8 inches, and 1.4 inches.

Now, to get the total amount of snowfall we add all the four snowfalls of the year:

$1.6\ inches+2.2\ inches+1.8\ inches+1.4\ inches\\\\=7\ inches.$

Therefore, the total amount of snow that fell is 7 inches.

8 0

4 years ago

What is the following simplified product? Assume x 0.<br> (sqrt6x^2+4sqrt8x^3)(sqrt9x-xsqrt5x^5)

e-lub [12.9K]

Answer:

c

Step-by-step explanation:

Keep in mind, whatever is inside of the square root, stays inside of the square root, and whatever is outside, stays outside, they don't multiply together. With parenthesis, exponents multiply, if there's no parenthesis, the exponents don't multiply. In this case, the exponents add.

Multiply each one together:

sqrt(6x^2) x sqrt(9x) = sqrt(54x^3)

sqrt(6x^2) x -(x sqrt(5x^5)) = -x sqrt(30x^7)

4 sqrt(8x^3) x sqrt(9x) = 4 sqrt(72x^4)

4 sqrt(8x^3) x -(x sqrt(5x^5)) = -4x sqrt(40x^8)

Then simplify:

sqrt(54x^2) = 3x sqrt(6x)

x sqrt(30x^7) = -x^4 sqrt(30x)

4 sqrt(72x^4) = 24x^2 sqrt(2)

-4x sqrt(40x^8) = -8x^5 sqrt(10)

5 0

3 years ago

A 20 year par value bond with semi-annual coupons at a nominal annual rate of 8% convertible semi-annually is purchased at a pri

trasher [3.6K]

Answer:

3.216%

Step-by-step explanation:

This bond sells at a higher price or value, which means that its coupon is bogus of market interest rate. Therefore, the minimum yield rate that accounts for the possibility of the bond being called is calculated at the earliest possible call date. Let say exactly 15 years from the date of purchase, because that would be the most disadvantageous date for the bondholder for the call to occur.

The minimum semiannual yield:

j= i²/2

i² = 2j

which therefore satisfies the expression below for the worst possible case scenario yield:

1722.25 = 0.04*1100* $a]_30$ + $\frac{1100}{(1+j)^30}$

Also, with the use of a financial calculator (making sure that the calculator is not in BGN mode)

1722.25 PV, -44 PMT, -1100 FV, 30 N, CPT 1/Y.

j can be found to be 1.608245%. The corresponding nominal annual rate compounded semiannually is (X) = i² = 2j =3.216%

6 0

3 years ago

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .

Verify that $(x + 2)\, (x + 3)$ indeed expands to the original polynomial:

$\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}$ .

4 0

3 years ago