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larisa [96]
2 years ago
6

How do you do this? ​

Mathematics
1 answer:
ad-work [718]2 years ago
8 0

a) The ratio of the perimeters is the same as the scale factor, so the ratio is the perimeters is 2/3.

b) The perimeter of triangle ABC is 36\left(\frac{3}{2} \right)=\boxed{54 \text{ ft}}

c) The ratio of the areas is the scale of the scale factor. In this case, the ratio is (2/3)^{2}=\boxed{4/9}

d) The area of FDE is 36(4/9)=\boxed{16 \text{ ft}^{2}}

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A rectangle is drawn with the dimensions shown. The area is listed inside each rectangle.
lutik1710 [3]

Answer:

the awnser is 45

Step-by-step explanation:

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5 0
3 years ago
[PROBABILITY] THERE ARE FOUR PEOPLE IN A ROOM THAT HAVEN'T MET BEFORE. THEY ARE TOLD TO SHAKE HANDS, EXACTLY ONCE, OF EVERY OTHE
Ivahew [28]

Answer:

6

Step-by-step explanation:

Let the 4 people be A, B, C and D. If each of them shakes hands with another person exactly one time then that means

A shakes with B, C and D. So 3 handshakes

B already shakes with A. So B shakes with C and D. 2 handshakes

C already shakes with A and B. So C shakes with D only. 1 handshake.

D already shake hand with all above.

Total handshakes: 3 + 2 + 1 = 6

8 0
3 years ago
Find the area between the two functions
Inga [223]

The area between the two functions is 0

<h3>How to determine the area?</h3>

The functions are given as:

f₁(x)= 1

f₂(x) = |x - 2|

x ∈ [0, 4]

The area between the functions is

A = ∫[f₂(x) - f₁(x) ] dx

The above integral becomes

A = ∫|x - 2| - 1 dx (0 to 4)

When the above is integrated, we have:

A = [(|x - 2|(x - 2))/2 - x] (0 to 4)

Expand the above integral

A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]

This gives

A = [2 - 4] - [-2- 0]

Evaluate the expression

A = 0

Hence, the area between the two functions is 0

Read more about areas at:

brainly.com/question/14115342

#SPJ1

5 0
1 year ago
I WILL GIVE BRAINLIEST!!!!<br><br> whose bored!!!!<br><br> 2+2=4
DENIUS [597]

Answer:

Yes and no, there are many different ways to put it ;)

8 0
2 years ago
Read 2 more answers
The time for a professor to grade an exam is normally distributed with a mean of 16.3 minutes and a standard deviation of 4.2 mi
dangina [55]

Answer:

A.0.4477

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 16.3, \sigma = 4.2

What is the probability that a randomly selected exam will require between 14 and 19 minutes to​ grade?

This probability is the pvalue of Z when X = 19 subtracted by the pvalue of Z when X = 14. So

X = 19

Z = \frac{X - \mu}{\sigma}

Z = \frac{19 - 16.3}{4.2}

Z = 0.64

Z = 0.64 has a pvalue of 0.7389.

X = 14

Z = \frac{X - \mu}{\sigma}

Z = \frac{14 - 16.3}{4.2}

Z = -0.55

Z = -0.55 has a pvalue of 0.2912

0.7389 - 0.2912 = 0.4477

So the correct answer is:

A.0.4477

7 0
2 years ago
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