The answer is standard form. When the equation is set up as Ax + By = C where A and B are coefficients.
B. 13
12^2 + 5^2 = c^2
169 = c^2
13 = c
please mark as brainliest :D
Answer:
-9
Step-by-step explanation:
x² -16 = (x -4)(x +4)
This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).
... For x-4 = ±1, x = 3 or 5
... For x+4 = ±1, x = -3 or -5
The values of x that are ±3 both give |x²-16| = 7, a prime.
The values of x that are ±5 both give |x²-16| = 9, not a prime.
The two values of x that are of interest are x=-3 and x=3. Their product is ...
... (-3)·(3) = -9
6 is neither equal to 0 nor equal to 7, so the last "piece" of h(x) applies. Then
h(6) = 3•6 - 2 = 18 - 2 = 16
The area of the sector is
.. Asector = (1/2)r^2*θ = (1/2)*(8.35 ft)^2*(π*260°/180°) ≈ 158.195 ft^2
The area of the triangle is
.. Atriangle = (1/2)r^2*sin(θ) = (1/2)*(8.35 ft)^2*sin(100°) ≈ 34.332 ft^2
The shaded area is
.. A = Asector +Atriangle
.. = 158.195 ft^2 +34.332 ft^2
.. ≈ 192.5 ft^2
