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il63 [147K]
2 years ago
7

How can you find the magnitude of a vector v→=

Mathematics
1 answer:
dalvyx [7]2 years ago
4 0

Answer:

The magnitude of a vector is its <u>length</u>.

To calculate the magnitude of a vector in any number of dimensions, square root the sum of the squares of each dimension.

Therefore, if  \vec v=(x,y)  then its magnitude is:

|v|=\sqrt{x^2+y^2}

Similarly, if  \vec v=(x,y,z)  then its magnitude is:

|v|=\sqrt{x^2+y^2+z^2}

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A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
Find the slope of the tangent line to the curve f(x)=e^(x) at (0.4,1.49)
almond37 [142]

Answer:

1.49

Step-by-step explanation:

In order to find the slope of the tangent line to a given equation, and in a given point, we need to:

1. Find the first derivative of the given function.

2. Evaluate the first derivative function in the given point.

1. Let's find the first derivative of the given function:

The original function is f(x)=e^{x}

But remeber that the derivative of  e^{x} is  e^{x}

so, f'(x)=e^{x}

2. Let's evaluate the first derivative function in the given point

The given point is (0.4,1.49) so:

f'(x)=e^{x}

f'(0.4)=e^{0.4}

f'(x)=1.49

Notice that the calculated slope of the tangent line is equal to the y-coordinate of the given point because f'(x)=f(x). In conclusion, the slope of the tangent line is equal to 1.49.

8 0
3 years ago
Suppose the function y = 30,000(1.06)x models the annual profit for a small business x years after 2000. Find the profit at the
goldfiish [28.3K]
From 2000 to 2011, there are 11 years. From the given function, we can calculate the profit for a small business at the end of 2011 by substituting 11 to the x of the given equation. 
                                         y = (30,000)(1.06)(11)
                                         y = 349,800
Thus, the profit at the end of 2011 is approximately $349,800. 
4 0
3 years ago
harriet is cultivating a strain of bacteria has doubled by the end of every second hour. how many bacteria will harriet have in
Black_prince [1.1K]

Answer:

n2^3 bacteria, n being the initial population.

Step-by-step explanation:

compound growth equation: P=n2^t

P is total population

n is initial population

t is time

since it doubles every second hour, and there are 6 hours

6hours/2hours= doubles 3 times, thats why t=3.

7 0
3 years ago
The sum of two numbers is equal to 63, and their difference is equal to 12. Find the numbers ​
Ainat [17]

Answer:

25.5   and   37.5

Step-by-step explanation:

x+y=63

x-y = 12    then   x = 12 + y      sub this into the first equation

(12+y)    + y = 63

12 + 2y = 63

2y = 51

y = 25.5     then x = 37.5

6 0
2 years ago
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