Given that,
ABC and ADC are triangles.
The area of ΔADC is 52 m².
Suppose , AD is the median.
According to figure,
We need to find the area of ΔABC
Using theorem of triangle
Here, Δ ADB = Δ ADC
So, 
Put the value of Δ ADC
Hence, The area of ΔABC is 104 m².
Answer:
Answer: 111∘
Step-by-step explanation:
Answer:
The Inverse Tangent Function (arctan)
Graph of y = tan x.
Answer: 9" by 7"
Step-by-step explanation:
let the dimensions of the rectangle be x and y
equation 1: xy=63
equation 2: 2(x+y)=32
first, rearrange the terms
(1′): y=63/x
(2′): y=16−x
(1′)-(2′): 0=63/x−16+x
multiply the equation by x
0=x2−16x+63
0=(x−9)(x−7)
so x = 7 or x = 9
from this, y = 9 when x = 7 and y = 7 when x = 9
so, the dimension of the rectangle is 9″ by 7″
