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Ipatiy [6.2K]
2 years ago
15

Gerald has a punch bowl in the shape of a hemisphere as shown below.

Mathematics
1 answer:
zmey [24]2 years ago
6 0

The closest to the maximum number of cups the punch bowl can hold is 30

<h3>How to determine the number of cups?</h3>

The given parameters are:

1 cup = 15 cubic inches

Diameter of bowl, d = 12 inches

The radius is the half of the diameter.

So, we have:

r = 6

The volume of the bowl is then calculated using:

V = \frac{2}{3}\pi r^3

This gives

V = \frac{2}{3}\pi * 6^3

Evaluate

V = 452.16

The maximum number of cups is then calculated using:

Cups = 452.16/15

Evaluate

Cups = 30.1444

Approximate

Cups = 30

Hence, the closest to the maximum number of cups the punch bowl can hold is 30

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

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2 years ago
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alexira [117]

Answer:

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Step-by-step explanation:

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2 years ago
Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un
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Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

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width = 2w+9

Area of road with pool =  (2w+15) (2w+9)

= 4w^2+30w+18w+135\\\\=4w^2+48w+135

Area of road = (Area of road with pool ) -(area of pool)

\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\  w=-14\ or \ w=2

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0
3 years ago
What does to solve the equation x - 2 = 9 (hint: you would need to subtract 2) form both sides of the equation am I correct?
geniusboy [140]

Answer:

I think the answer to X = 11.

Step-by-step explanation:

X - 2 = 9, correct?

11 - 2 = 9.

I hope this can help! Please correct me

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