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Lady_Fox [76]
3 years ago
5

Determine whether the following statement is always, sometimes, or never true.

Mathematics
1 answer:
Vlad [161]3 years ago
5 0

Answer:

this statement is true because then the triangles will be congruent by rhs axiom

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A container built for transatlantic shipping is constructed in the shape of a right rectangular prism. Its dimensions are 7 ft b
____ [38]

Given:

Dimensions are 7 ft by 5 ft by 8.5 ft

Contents weigh 0.21 pound

Contents worth $8.80 per pound

Find-: value of container contents.

Sol:

Volume is:

\begin{gathered} Volume\text{ = }7\times5\times8.5 \\  \\ =297.5 \end{gathered}

The formula of density is:

\text{ Density =}\frac{\text{  Mass}}{\text{ Volume}}

So,

\begin{gathered} 0.21=\frac{\text{ Weight  of contents in container}}{\text{ Volume of container}} \\  \\ 0.21=\frac{\text{ Weight}}{297.5} \\  \\ 0.21\times297.5=\text{ Weight} \\  \\ \text{ Weight of contents in container = }62.475\text{ Pound} \end{gathered}

Now $8.80 per pound

For 62.475 pounds the value is:

\begin{gathered} =62.475\times8.80 \\  \\ =549.78 \end{gathered}

So the value of the container contents is 549.78

7 0
1 year ago
"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
Sorry last one :Multiply.<br><br> 2√⋅5√⋅11
DIA [1.3K]
Hey! You just have to square root the 2 and 5 then multiply by 11 so the answer I came up with is 34.78505426185218

I hope I helped!

4 0
3 years ago
Read 2 more answers
What can you say about the quotient, when you divide 23 by something equal to 1?
Gwar [14]

Answer: the quotient will be equal to 23

The equation to calculate what divided by 23 equals 1 is as follows:

X/23 = 1

Where X is the answer. When we solve the equation by multiplying each side by 23, you get get:

X = 23

Therefore, the answer to what divided by 23 equals 1 is 23

so the quotient will be equal to 23

Step-by-step explanation:

8 0
3 years ago
What is the volume of the rectangular prism 10.4mm 5mm 8mm
alina1380 [7]
The answer too this problem is 416.
7 0
3 years ago
Read 2 more answers
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