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<span>Given the quadratic equation: f(x) = -2x^2 - 2x - 1, the axis of symmetry can be obtained by finding the line that divides the function into two congruent or identical halves. Thus, it should pass through the vertex and is equal
to the x-coordinate of the vertex. </span>
<span>Note that a quadratic
equation in standard form: y = ax^2 + bx + c, has the vertex located at (h,k) where, h = -b/2a and k is determined by evaluating y at
h. In this case, a = -2, b = -2, thus, h = -0.5, k = 0.5. Thus, the vertex is located at (-0.5, 0.5) and the axis of symmetry is at x = -0.5. </span>
The equation of a circle is (x - h)^2 + (y - k)^2 = r^2
x and y are left alone in a circle equation, while h and k are the coordinates of the center.
Thus, our equation is (x - 7)^2 + (y + 2)^2 = 61
We can solve for x by raising both sides to the -3 power (which is the reciprocal of -1/3):
(c^-1/3)^-3 = x^-3
c^1=x^-3
c=x^-3
Since the exponent on the x is a negative, we have to move it to the denominator to make it positive:
c= 1/x³
Answer:
P = 16x + 8
Step-by-step explanation:
Perimeter of a rectangle
= 2(L + W)
Given
L = 5x + 4 and
W = 3x
Therefore
Perimeter = 2(5x + 4 + 3x)
Rearrange the expression
P = 2(5x + 3x + 4)
P = 2(8x + 4)
Now expand the bracket
P = 2 x 8x + 2 x 4
P = 16x + 8
