Answer:
Waves superimpose upon each other when they collide, while objects do not
Step-by-step explanation:
The main difference between the collision of waves and the collision of objects is simply the superposition principle.
When waves collide, they do not do so in the same way objects do. The superposition principle explains that waves can either collide in a constructive or destructive manner.
Case A: Waves colliding in a constructive manner
When waves collide in a constructive manner, this means that they are in phase, in simpler terms, it means that they have the same shape as they move through space-time. Constructive collision leads to a formation of a bigger wave with a higher amplitude. This is how stereo speakers operate. They produce louder sounds by releasing the same audio waves, causing them to superimpose upon each other.
Case B: Waves colliding in a destructive manner:
When waves are out of phase(i.e do not have the same shape as they move through space-time) and they collide, they try to cancel each other out, leading to a new wave with a weaker amplitude. This is how noise-cancelling headphones work. They emit an equal and opposite wave sound to the noise around your ears, thus cancelling it out.
1, 3, 5
Or
Ratio of white flowers to pink flowers
Ordered pair (8,12)
Number of pink and white flowers in one row of molly's garden
Answer:
(arranged from top to bottom)
System #3, where x=6
System #1, where x=4
System #7, where x=3
System #5, where x=2
System #2, where x=1
Step-by-step explanation:
System #1: x=4
To solve, start by isolating your first equation for y.
Now, plug this value of y into your second equation.
System #2: x=1
Isolate your second equation for y.
Plug this value of y into your first equation.
System #3: x=6
Isolate your first equation for y.
Plug this value of y into your second equation.
System #4: all real numbers (not included in your diagram)
Plug your value of y into your second equation.
<em>all real numbers are solutions</em>
System #5: x=2
Isolate your second equation for y.
Plug in your value of y to your first equation.
System #6: no solution (not included in your diagram)
Isolate your first equation for y.
Plug your value of y into your second equation.
<em>no solution</em>
System #7: x=3
Plug your value of y into your second equation.
Answer:
Step-by-step explanation:
Additive inverse of (5a² - 4a + 3) should be added to make them zero
(5a² - 4a + 3) + (-5a² + 4a - 3)= <u>5a² - 5a² </u> <u>- 4a + 4a</u> <u>+ 3 - 3</u>
= 0
