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kkurt [141]
1 year ago
8

Please i need it for now PLSSSS

Mathematics
1 answer:
bearhunter [10]1 year ago
4 0

The measure of the other side of a quadrilateral is 3\sqrt{13} cm.

In the given quadrilateral one side is unknown we need to find the unknown side.

By dividing the given quadrilateral into a rectangle and a triangle we can find the other side.

<h3>What is Pythagoras theorem?</h3>

The Pythagoras theorem states that if a triangle is right-angled, then the square of the hypotenuse is equal to the sum of the squares of the other two sides. That is, c^{2}=a^{2}+b^{2}.

Now, x^{2} =9^{2}+6^{2}=81+36=17

⇒x=\sqrt{13 \times 9} =3\sqrt{13}

Therefore, the measure of the other side of a quadrilateral is 3\sqrt{13} cm.

To learn more about Pythagoras' theorem visit:

brainly.com/question/343682.

#SPJ1

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Step-by-step explanation:

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Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,
sweet [91]

Answer:

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

f'' = x - \frac{3}{2}

f' = \int {\left(x-\frac{3}{2}\right) } \, dx

f' = \int {x} \, dx -\frac{3}{2}\int \, dx

f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C, where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative (f'(4) = 1):

1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C

C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)

C = -1

The first derivative is y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1, and the particular solution is found by integrating one more time and using the initial condition (f(0) = 0):

y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1  \right)} \, dx

y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx

y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C

C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0

C = 0

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

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Answer:

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Step-by-step explanation:

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