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kkurt [141]
2 years ago
8

Please i need it for now PLSSSS

Mathematics
1 answer:
bearhunter [10]2 years ago
4 0

The measure of the other side of a quadrilateral is 3\sqrt{13} cm.

In the given quadrilateral one side is unknown we need to find the unknown side.

By dividing the given quadrilateral into a rectangle and a triangle we can find the other side.

<h3>What is Pythagoras theorem?</h3>

The Pythagoras theorem states that if a triangle is right-angled, then the square of the hypotenuse is equal to the sum of the squares of the other two sides. That is, c^{2}=a^{2}+b^{2}.

Now, x^{2} =9^{2}+6^{2}=81+36=17

⇒x=\sqrt{13 \times 9} =3\sqrt{13}

Therefore, the measure of the other side of a quadrilateral is 3\sqrt{13} cm.

To learn more about Pythagoras' theorem visit:

brainly.com/question/343682.

#SPJ1

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Let X and Y be joint continuous random variables with joint density function fpx, yq " # e ´y y 0 ă x ă y, 0 ă y ă 8 0 otherwise
Assoli18 [71]

Answer:

For X, the parameter

is λX = 1/2 and for Y it is λY = 1. Using the formula sheet, Mean is

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4 years ago
I just learned this today and it’s a little confusing , is there anyone that could explain how to do these problems for me ?
evablogger [386]

Step-by-step explanation:

I'll do the first problem as an example.

∠P and ∠H both have one mark.  That means they're congruent.

∠T and ∠G both have two marks.  So they're congruent.

∠W and ∠D both have three marks.  So they're congruent.

So we can write a congruence statement:

ΔPTW ≅ ΔHGD

We can write more congruence statements by rearranging the letter, provided that corresponding pairs have the same position (P is in the same place as H, etc.).  For example:

ΔWPT ≅ ΔDHG

ΔTWP ≅ ΔGDH

3 0
4 years ago
Find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3). express answer in standard form
Anestetic [448]

Answer:

Final answer is x-6y=23

Step-by-step explanation:

We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).

So first we need to find the slope of given line.

rewirite x=6y-5 in y=mx+b form

x+5=6y

\frac{1}{6}x+\frac{5}{6}=y

Compare given equation with y=mx+b

we get: m=1/6

We know that parallel equations has equal slope.

Then slope of required line m=1/6

Now plug the given point (5,-3) and slope m=1/6 into point slope formula:

y-y_1=m\left(x-x_1\right)

y-(-3)=\frac{1}{6}\left(x-5\right)

y+3=\frac{1}{6}x-\frac{5}{6}

y=\frac{1}{6}x-\frac{5}{6}-3

y=\frac{1}{6}x-\frac{23}{6}

Now we need to rewrite that equation in standard form. Ax+By=C.

6y=x-23

x-23=6y

x-6y=23

Hence final answer is x-6y=23

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guajiro [1.7K]
<h3>AG = 27 and VA = 24. What is TO? </h3>

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3 years ago
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