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2 years ago

Please i need it for now PLSSSS

Mathematics

1 answer:

bearhunter [10]2 years ago

4 0

The measure of the other side of a quadrilateral is $3\sqrt{13}$ cm.

In the given quadrilateral one side is unknown we need to find the unknown side.

By dividing the given quadrilateral into a rectangle and a triangle we can find the other side.

<h3>What is Pythagoras theorem?</h3>

The Pythagoras theorem states that if a triangle is right-angled, then the square of the hypotenuse is equal to the sum of the squares of the other two sides. That is, $c^{2}=a^{2}+b^{2}$ .

Now, $x^{2} =9^{2}+6^{2}=81+36=17$

⇒ $x=\sqrt{13 \times 9} =3\sqrt{13}$

Therefore, the measure of the other side of a quadrilateral is $3\sqrt{13}$ cm.

To learn more about Pythagoras' theorem visit:

brainly.com/question/343682.

#SPJ1

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Need help with work g

Nonamiya [84]

Answer:

21 meters

Step-by-step explanation:

First find the circumference of the tire:

c = πd

c = 3.14(670)

c = 2103.8

Multiply by 10 to find the distance the bike has travelled:

2103.8*10 = 21,038

Convert millimeters to meters:

21,038 millimeters ≈ 21 meters

8 0

3 years ago

Read 2 more answers

Two number cubes are rolled for two separate events:

andrew11 [14]

Answer: $\bold{P(B|A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{11}{30}}$

<u>Step-by-step explanation:</u>

The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)

$P(B|A)=\dfrac{P(B\cap A)}{P(A)}$

P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)

(2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)

(3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)

(4, 5), (4, 4), (4, 3), (4, 2), (4, 1)

(5, 4), (5, 3), (5, 2), (5, 1)

(6, 3), (6, 2), (6, 1)

= 30

P(B) = (1, 2), (2, 1) sum = 3

(1, 5), (2, 4), (3, 3), (4, 2), (5, 1) sum = 6

(3, 6), (4, 5), (5, 4), (5, 4), (6, 3) sum = 9

(6, 6) sum = 12

= 12

P(A ∩ B) = (1, 2), (2, 1)

(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

(3, 6), (4, 5), (5, 4), (5, 4), (6, 3)

= 11

7 0

3 years ago

Bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

vodomira [7]

Answer:

Reference angles are always acute.

We can find the reference angle with the "formula"

−

, where

is our given angle.

We can plug

into our expression to get

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Thus, our reference angle is

5 0

3 years ago

15 points !!!!!!!!!!!!!!!!!!!!!!!!1

zmey [24]

Five is the answer hope that helps

7 0

3 years ago

Each of 16 students measured the circumference of a tennis ball by four different methods, which were:Method A: Estimate the cir

lys-0071 [83]

Answer:

a) $\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

b) $Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

c) $\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

Step-by-step explanation:

Data given

Assuming the following data:

Method A: 18.0, 18.0, 18.0, 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0,25.0,26.0,26.4

Method B: 18.8, 18.9, 18.9, 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0, 22.0,22.0,23.6

Method C: 20.2, 20.5, 20.5, 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5,21.5,21.5,21.6

Method D: 20.0, 20.0, 20.0,-20.0, 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5, 21.6, 22.1,22.3.

Part a

The sample mean is defined as:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

If we apply this formula for the four methods we got:

$\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

Part b

Since the total number of points for each method is 16 and this is an even number we need to calculate the median as the average between the 8th and the 9th position of the data ordered from the smallest to the largest. If we do this we have that:

$Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

Part c

The trimmed mean by 20% means that we need to calculate removing the 20% from each of the tails, the 20% of 16 is 3.2, so we need to remove 3 observations from both ends of the data like this:

Method A: 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0

Method B: 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0

Method C: 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5

Method D: 20.0 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5.

If we calculate the mean for each method we got:

$\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

3 0

3 years ago